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Chemistry Form 4 • MODULE


                  EXERCISE / LATIHAN


                1   The equation shows the reaction between zinc and hydrochloric acid.
                    Persamaan menunjukkan tindak balas antara zink dengan asid hidroklorik.

                                                          Zn + 2HCl   ZnCl  + H
                                                                          2    2
                                                                                               3
                    Calculate the mass of zinc required to react with excess hydrochloric acid to produce 6 dm  of hydrogen gas at room
                                                                                            3
                    conditions. [Relative atomic mass: Zn = 65, Cl = 35.5, 1 mole of gas occupies 24 dm  at room conditions]
                                                                                                    3
                    Hitungkan jisim zink yang perlu ditindakbalaskan dengan asid hidroklorik berlebihan untuk menghasilkan 6 dm  gas hidrogen pada
                    keadaan bilik. [Jisim atom relatif: Zn = 65, Cl = 35.5, 1 mol gas menempati 24 dm  pada suhu bilik]
                                                                                3
                                  6 dm 3
                    Mol of H  =             = 0.25 mol
                                    3
                           2   24 dm  mol –1
                    From the equation,
                          1   mol of H  : 1 mol of Zn
                                  2
                         0.25 mol of H  : 0.25 mol of Zn
                                  2
                         Mass of Zn = 0.25 × 65 = 16.2 g


                2   The equation shows the reaction between potassium and oxygen.
                    Persamaan berikut menunjukkan tindak balas antara kalium dengan oksigen.
                                                              4K + O    2K O
                                                                    2     2

                    Calculate the mass of potassium required to produce 23.5 g of potassium oxide. [Relative atomic mass: K = 39, O = 16]
                    Hitungkan jisim kalium yang diperlukan untuk menghasilkan 23.5 g kalium oksida. [Jisim atom relatif: K = 39, O = 16]

                                    23.5        23.5
                    Mol of K O =             =        = 0.25 mol
                           2    (2 × 39 + 16)    94
                    From the equation,
                          2   mol of K O : 4 mol of K
                                  2
                        0.25 mol of K O : 0.5 mol of K
                                  2
                         Mass of K = 0.5 mol × 39 g mol  = 19.5 g
                                                  –1


                3   The equation shows the decomposition of hydrogen peroxide.
                    Persamaan menunjukkan penguraian hidrogen peroksida.

                                                             H O    H O + O
                                                               2  2  2     2
                    Balance the equation above. Calculate the number of moles of H O  that decomposes if 11.2 dm  oxygen gas is collected
                                                                                                    3
                                                                            2
                                                                          2
                    at STP. [Relative Atomic mass: H = 1, O = 16, molar volume of gas = 22.4 dm  mol  at STP]
                                                                                      3
                                                                                           –1
                                                                                          3
                    Seimbangkan persamaan di atas. Hitung bilangan mol H O  yang telah terurai sekiranya 11.2 dm gas oksigen dikumpulkan pada STP.
                                                               2
                                                             2
                                                                   3
                                                                      –1
                    [Jisim atom relatif: H = 1, O = 16, isi padu molar gas = 22.4 dm  mol  pada STP]
                                 11.2 dm 3
                    Mol of O  =   22.4 dm  mol –1   = 0.5 mol
                           2
                                      3
                    From the equation,
                          1   mol of O   : 2 mol of H O
                                 2
                                             2
                                               2
                         0.5 mol of O  : 1.0 mol of H O
                                 2
                                              2
                                                2
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                                                                                                                         Nilam Publication Sdn. Bhd.
        02-Chem F4 (3P).indd   45                                                                                  12/9/2011   5:59:09 PM
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