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Soalan Berformat SPM

Kertas 1/Paper 1
1. 2. Diberi fungsi f (x) = 2mx dan g(x) = 3x + n, di mana m
KLON KLON dan n adalah pemalar. Ungkapkan n dalam sebutan m
SPM hk SPM supaya fungsi gubahan gf memetakan 2 kepada dirinya
sendiri.
Given the function f(x) = 2mx and g(x) = 3x + n, where m and n
are constants. Express n in terms of m such that the composite
function gf maps 2 to itself. KBAT Mengaplikasi
[3 markah/marks]
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p q r
gf (2) = 2
Rajah di atas menunjukkan fungsi gubahan hk yang 3(2m(2)) + n = 2
memetakan p kepada r. Nyatakan 12m + n = 2
The above diagram shows the composite function hk which n = 2 – 12m
maps p to r. State
(a) fungsi yang memetakan q kepada r.
the function that maps q to r.
(b) k h (r) KBAT Mengaplikasi
–1 –1
[2 markah/marks]
(a) h
(b) p

3. Diberi fungsi k : x → 2x + 9, cari 4. Diberi f : x → 1 – 2mx, g : x → 5x – n dan fg : x → m x + n.
2
Given the function k : x → 2x + 9, find Cari nilai-nilai m dan n.
KLON KLON
SPM (a) nilai x apabila k(x) = 3x. SPM Given f : x → 1 – 2mx, g : x → 5x – n and fg : x → m x + n.
2
the value of x when k(x) = 3x. Find the values of m and n. KBAT Mengaplikasi
(b) nilai a dengan keadaan k(a + 9) = a. [4 markah/marks]
the value of a such that k(a + 9) = a
KBAT Mengaplikasi fg(x) = 1 – 2m(5x – n)
[4 markah/marks] = 1 – 10mx + 2mn
m x + n = –10mx + 2mn + 1
2
(a) 2x + 9 = 3x Bandingkan pekali x
–x = –9 m = –10m
2
x = 9 m + 10m = 0
2
m = 0, m = –10
(b) 2(a + 9) + 9 = a
2a + 27 = a Bandingkan pemalar
a = –27 n = 2mn + 1
Jika m = 0 ⇒ n = 1
Jika m = –10, ⇒ n = 2(–10)n + 1
n = –20n + 1
21n = 1
n = 1
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