Page 16 - Modul A+1 Matematik Tambahan Tingkatan 5
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Uji Kendiri       1.4

                     1.  Rajah menunjukkan sebuah bulatan berjejari  6.5 cm    2.  Rajah menunjukkan sepotong tembikai dengan keratan
                      dan  berpusat  O. Diberi  bahawa  panjang  AB adalah   rentas seragamnya berbentuk sektor berpusat O.
                      sama dengan panjang AC.                            The diagram shows a uniform cross-section of a piece  of
                      The diagram  shows a circle with a radius of  6.5 cm and    watermelon in the shape of a sector with centre O.
                      centre O. Given that the length of AB is the same as AC.                           KBAT  Menilai   BAB 1
                                                       KBAT  Menilai
                                                                                           10 cm
                                             B
                                                                                           O
                                                                                    A       θ
                                                                                       C
                                           O                                                     D
                                      50°
                                  A                                                                B
                                                C
                                                                         Diberi bahawa panjang lengkok AB dan CD masing-
                                                                         masing ialah 20 cm dan 16 cm dengan bahagian ABCD
                      Cari/Find                                          tidak  boleh  dimakan.  Jika  AC = 2 cm  dan  panjang
                      (a)  perimeter kawasan berlorek,
                          the perimeter of the shaded region,            potongan tembikai itu ialah 10 cm, cari
                      (b)  luas kawasan berlorek.                        Given that the arc length AB and CD is 20 cm and 16 cm
                                                                         respectively with the portion ABCD is not edible. If AC = 2  cm
                          the area of the shaded region.                 and the length of a piece of the watermelon is 10 cm, find
                      (a)  ∠BAO = 25°                                    (a)  nilai q, dalam radian,
                          Panjang AB = 2(6.5 kos 25°)                       the value of q, in radians,
                                   = 11.78 cm                            (b)  isi padu bahagian yang boleh dimakan.
                          Panjang lengkok AB                             (a)   the volume of the area that can be eaten.
                                                                                 OC(q) = 16 ..............a
                                       p
                          = 6.5 × 130° ×  180°                                (OC + 2)q = 20
                          = 14.75 cm                                         OC(q) + 2q = 20 ..............b
                          Perimeter kawasan berlorek                        b – a:  2q = 20 – 16
                                                                                     q = 2 rad
                          = 2(11.78) + 2(14.75)                                   16
                          = 53.06 cm                                     (b)  OC =    2   = 8 cm
                      (b)  Luas kawasan berlorek                            Isi padu =   (8) (2) × 10
                                                                                     1
                                                                                         2
                                                               ]
                            [
                                             p
                                                  1
                                                                                     2
                             1
                                                 –   (6.5)  sin 130°
                        ©PAN ASIA PUBLICATIONS
                               × 6.5  × 130° ×
                          = 2
                                                       2
                                   2
                                            180°
                                                  2
                             2
                                                                                   = 640 cm


                                                                                           3
                          = 63.5 cm 2
                                                                              SPM
                                                  Soalan Berformat            SPM
                                                           Kertas 1  Paper 1
                                                          Bahagian A/Section A
                  1.  Rajah menunjukkan sebuah bulatan berpusat  O dengan jejari 5 cm. Diberi  OQTC ialah   C       T
                     sebuah segi empat tepat dengan luas 40 cm , cari                                          B
                                                       2
                     The diagram shows a circle with centre O and a radius of 5 cm. Given OQTC is a rectangle with an   θ
                               2
                     area of 40 cm , find  KBAT  Menilai                                                O       A   Q
                     (a)  nilai q, dalam radian,
                        the value of q, in radians,                             [2 markah/marks]
                     (b)  luas sektor OAB,
                        the area of the sector OAB,                             [2 markah/marks]
                     (c)  perimeter kawasan berlorek.
                        the perimeter of the shaded region.                     [2 markah/marks]
                                                                                                        )
                     (a)  OC × CT = 40                                   (c)  Panjang lengkok AB = 5 ( π  – 1.01  = 2.80 cm
                          5 × CT = 40                                                            2
                           º CT = 8 cm                                       Panjang BT = ! 8  + 5  – 5 = 4.43 cm
                                                                                              2
                                                                                          2
                            tan q =  8                                       Perimeter = 2.80 + 4.43 + 3 + 5 = 15.23 cm
                                   5
                               q = 58° ×   π   = 1.01 rad
                                       180°
                                             (
                                                     )
                                         1
                     (b)  Luas sektor OAB =   (5) 2 π  – 1.01  = 7.01 cm 2
                                         2    2
                                                                  13
         01 Modul Series MateTam Tg5.indd   13                                                                    04/10/2021   2:15 PM
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