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Thus, subject to the constraint   , the maximum value of the quadratic form is , which occurs if                          ,

; and the minimum value is                    , which occurs if      ,             . Moreover, alternative bases for

the eigenspaces can be obtained by multiplying the basis vectors above by −1. Thus the maximum value,          , also occurs if
                                                                                                                .
,                         ; similarly, the minimum value,        , also occurs if                ,

DEFINITION

A quadratic form    is called positive definite if          for all  , and a symmetric matrix A is called a positive
definite matrix if
                    is a positive definite quadratic form.

The following theorem is an important result about positive definite matrices.

THEOREM 9.5.2

A symmetric matrix A is positive definite if and only if all the eigenvalues of A are positive.

Proof Assume that A is positive definite, and let be any eigenvalue of A. If x is an eigenvector of A corresponding to ,

then and            , so

                                                                                                               (7)

where is the Euclidean norm of x. Since                          it follows that , which is what we wanted to

show.                                                                              for all . But if , we can
Conversely, assume that all eigenvalues of A are positive. We must show that

normalize x to obtain the vector  with the property                  . It now follows from Theorem 9.5.1 that

where is the smallest eigenvalue of A. Thus,

Multiplying through by yields
which is what we wanted to show.

EXAMPLE 3 Showing That a Matrix Is Positive Definite
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