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THEOREM 11.6.4
Steady-State Vector .
The steady-state vector q of a regular transition matrix P is the unique probability vector that satisfies the equation
To see this, consider the matrix identity . By Theorem 11.6.2, both and approach Q as . Thus, we
have . Any one column of this matrix equation gives . To show that q is the only probability vector that satisfies this
equation, suppose r is another probability vector such that . Then also for , 2, …. When we let ,
Theorem 11.6.3 leads to .
Theorem 11.6.4 can also be expressed by the statement that the homogeneous linear system
has a unique solution vector q with nonnegative entries that satisfy the condition . We can apply this
technique to the computation of the steady-state vectors for our examples.
EXAMPLE 7 Example 2 Revisited
In Example 2 the transition matrix was
so the linear system is
(2)
This leads to the single independent equation
or
Thus, when we set , any solution of 2 is of the form
where s is an arbitrary constant. To make the vector q a probability vector, we set . Consequently,
is the steady-state vector of this regular Markov chain. This means that over the long run, 60% of the alumni will give a donation
in any one year, and 40% will not. Observe that this agrees with the result obtained numerically in Example 3.
EXAMPLE 8 Example 1 Revisited
In Example 1 the transition matrix was

