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7.4  Gravitational Potential Energy                     223



                  (a)                                                          (b)
                                                                                      y

                                                                                               Initially, energy
                                                                                   P 1
                                                                                               is all potential.

                                                                                                   At the bottom,
                                                                                   y 1             energy is all kinetic.


                                                                                                       P 2
                                                                                   O                      x

                                                                              FIGURE 7.23 (a) A roller coaster. (b) Profile
                                                                              of a roller coaster. The roller-coaster car descends
                                                                              from P to P .
                                                                                       2
                                                                                   1

                        which gives
                                                        2
                                      v   22   9.81 m/s   38 m   27m/s
                                       2
                        Note that according to Eq. (7.41) the final velocity is independent of the mass of
                        the car; since both the kinetic energy and the gravitational potential energy are
                        proportional to mass, the mass cancels in this calculation.

                        COMMENT: This example illustrates how energy conservation can be exploited
                        to answer a question about motion. To obtain the final speed by direct computa-
                        tion of forces and accelerations would have been extremely difficult—it would have
                        required detailed knowledge of the shape of the path down the hill. With the Law
                        of Conservation of Energy we can bypass these complications.





                                                                      ENERGY CONSERVATION IN ANALYSIS
                       PROBLEM-SOLVING TECHNIQUES
                                                                      OF MOTION


                       As illustrated by the preceding example,the use of energy con-  y coordinate. However, the change in the potential energy
                       servation in a problem of motion typically involves three steps:  does not depend on the choice of this level, and therefore any
                                                                         choice will lead to the same result for the change of kinetic
                       1 First write an expression for the energy at one point of
                                                                         energy. Thus, you can make any choice of zero level, but
                          the motion [Eq. (7.38)].
                                                                         you must continue to use this choice throughout the entire
                       2 Then write an expression for the energy at another point  calculation. You will usually find it convenient to place the
                          [Eq. (7.39)].                                  zero level for the y coordinate either at the final position of
                       3 And then rely on energy conservation to equate the two  the particle (as in the preceding example), or at the initial
                          expressions [Eq. (7.40)].This yields one equation, which  position, or at some other distinctive height, such as the
                          can be solved for the unknown final speed or the unknown  bottom of a hill or the ground floor of a building. And always
                          final position (if the final speed is known).  remember that the formula U   mgy for the gravitational
                                                                         potential energy assumes that the y axis is directed verti-
                          Note that the value of the gravitational potential energy
                                                                         cally upward.
                       U   mgy depends on the level from which you measure the
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