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                                   276                  Mathematical Induction
                                       (b) Consider a tournament in which each contestant plays every other
                                          contestant exactly once, and one of them wins. We’ll say that a con-
                                          testant x is excellent if, for every other contestant y, either x beats y
                                          or there is a third contestant z such that x beats z and z beats y. Prove
                                          that there is at least one excellent contestant.
                                                             n
                                     5. For each n ∈ N, let F n = 2 (2 )  + 1. (These numbers are called the Fermat
                                       numbers, after the French mathematician Pierre de Fermat (1601–1665).
                                       Fermat showed that F 0 , F 1 , F 2 , F 3 , and F 4 are prime, and conjectured
                                       that all of the Fermat numbers are prime. However, over 100 years later
                                       Euler showed that F 5 is not prime. It is not known if there is any n > 4
                                       for which F n is prime.)
                                         Prove that for all n ≥ 1, F n = (F 0 · F 1 · F 2 ··· F n−1 ) + 2.
                                     6. Prove that if n ≥ 1 and a 1 , a 2 ,..., a n are any real numbers, then |a 1 +
                                       a 2 +· · · + a n |≤|a 1 |+|a 2 |+· · · +|a n |. (Note that this generalizes the
                                       triangle inequality; see exercise 12(c) of Section 3.5.)
                                     7. (a) Prove that if a and b are positive real numbers, then a/b + b/a ≥ 2.
                                                                        2
                                          (Hint: Start with the fact that (a − b) ≥ 0.)
                                       (b) Suppose that a, b, and c are real numbers and 0 < a ≤ b ≤ c.
                                          Prove that b/c + c/a − b/a ≥ 1. (Hint: Start with the fact that
                                          (c − a)(c − b) ≥ 0.)
                                       (c) Prove that if n ≥ 2 and a 1 , a 2 , ..., a n are real numbers such that
                                          0 < a 1 ≤ a 2 ≤ ... ≤ a n , then a 1 /a 2 + a 2 /a 3 +· · · + a n−1 /a n +
                                          a n /a 1 ≥ n.
                                     8. If n ≥ 2 and a 1 , a 2 ,. . . , a n is a list of positive real numbers, then the
                                    ∗
                                       number (a 1 + a 2 +· · · + a n )/n is called the arithmetic mean of the num-
                                                                   √
                                       bers a 1 , a 2 ,. . . , a n , and the number  n  a 1 a 2 ··· a n is called their geometric
                                       mean. In this exercise you will prove the arithmetic-geometric mean in-
                                       equality, which says that the arithmetic mean is always at least as large
                                       as the geometric mean.
                                       (a) Prove that the arithmetic-geometric mean inequality holds for lists of
                                          numbers of length 2. In other words, prove that for all positive real
                                                                   √
                                          numbers a and b,(a + b)/2 ≥  ab.
                                       (b) Prove that the arithmetic-geometric mean inequality holds for any
                                          list of numbers whose length is a power of 2. In other words, prove
                                          that for all n ≥ 1, if a 1 , a 2 ,. . . , a 2 is a list of positive real numbers,
                                                                     n
                                          then

                                                      a 1 + a 2 +· · · + a 2 n  2 n √
                                                                       ≥   a 1 a 2 ··· a 2 .
                                                                                   n
                                                             2 n
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