Page 38 - Steady Mate Tg1 - Book B

Matematik Tingkatan 1 Bab 6 Persamaan Linear

D Selesaikan setiap persamaan linear yang berikut. TP 3 ARAS R
Solve each of the following linear equations.

Contoh 1. 2x + 5 = –1 2. 5x – 4 = –9
3x + 2 = 8
2x + 5 – 5 = –1 – 5 5x – 4 + 4 = –9 + 4
3x + 2 – 2 = 8 – 2 2x = – 6 5x = – 5
3x = 6 2x –6 5x –5
= =
3x 6 2 2 5 5
=
3 3
x = –3 x = –1
x = 2

Contoh 3. 2x + 3 = 5 4. 5x – 4 = 3
5 2
4x + 5
= 3 2x + 3 5x – 4
3 × 5 = 5 × 5 × 2 = 3 × 2
5 2
4x + 5 2x + 3 = 25 5x – 4 = 6
× 3 = 3 × 3
3 2x + 3 – 3 = 25 – 3 5x – 4 + 4 = 6 + 4
4x + 5 = 9
2x = 22 5x = 10
4x + 5 – 5 = 9 – 5 2x 22 5x 10
= =
4x = 4 2 2 5 5
4x 4
= x = 11 x = 2
4 4
x = 1

Contoh 5. x – 5 = x – 2 6. – 4 x + 6 = 1 – x
4 9
2 x + 2 = 4 – x
3 Permudah x – 5 + 5 = x – 2 + 5 – 4 x + 6 – 6 = 1 – x – 6
kedua-dua belah 4 9
2 persamaan supaya x 4
x + 2 – 2 = 4 – x – 2 = x + 3 – x = –5 – x
3 sebutan yang ada 4 9
2 pemboleh ubah
x = 2 – x x 4
3 di satu belah dan – x = x + 3 – x – x + x = –5 – x + x
2 nombor di sebelah 4 9
x + x = 2 – x + x yang lain. 3 5
3 Simplify both sides – 4 x = 3 9 x = –5
2 x = 2 of the equation so
1
3 that the variable – 3 x × – 4 2 = 3 × – 4 2 5 x × 9 = –5 × 9
1
2 3 3 terms on one side 4 3 3 9 5 5
x × = 2 × and the numbers on
3 2 2 the other side. x = – 4 x = –9
x = 3
Contoh 7. 3(x + 1) = 2x – 4 8. 4(x – 3) = 2 – 3x
2(x + 4) = x + 5 Kembangkan 3x + 3 = 2x – 4 4x – 12 = 2 – 3x
Expand 3x + 3 – 3 = 2x – 4 – 3 4x – 12 + 12 = 2 – 3x + 12
2x + 8 = x + 5
3x = 2x – 7 4x = 14 – 3x
2x + 8 – 8 = x + 5 – 8
3x – 2x = 2x – 7 – 2x 4x + 3x = 14 – 3x + 3x
2x = x – 3
x = –7 7x = 14
2x – x = x – 3 – x 7x 14
x = –3 7 = 7
x = 2

© Penerbitan Pelangi Sdn. Bhd. 36