Page 40 - Steady Mate Tg1 - Book B

Matematik Tingkatan 1 Bab 6 Persamaan Linear

KANDUNGAN
Praktis Berfomat PT3

1. Diberi x + 5 = –3. Cari nilai x. Jawapan / Answer:
Given x + 5 = –3. Find the value of x.
3(6 – y) = 12
A –2 C –8 18 – 3y = 12
B 2 D 8 18 – 3y – 18 = 12 – 18
–3y = –6
2. Bulatkan persamaan linear dalam satu pemboleh ubah –3y –6
pada ruang jawapan. –3 = –3
Circle the linear equations in one variable in the answer
space. y = 2
[4 markah / 4 marks]
Jawapan / Answer: (c)
Mata / Point 1 2 3 4 5

2w 1 Bilangan peserta
10 – 7x = –0.5 5 + = 1 – 3 = r 1 2 x 6x 3
3 2r Number of participants
4g + g = 2 y + 4 = x
2
Jadual di atas menunjukkan skor yang diperoleh
6 + 4b = 2
peserta dalam satu kuiz matematik dalam talian.
2
1 – b = b
2t – 3 = s Peserta yang memperoleh pungutan mata melebihi
tiga akan diberikan hadiah.
4h – 2 = –3h 4 – vw = 6 The table shows the score obtained by participants in an
online mathematics quiz. Participant who scored more
than three points will be given prizes.
3. (a) Tulis persamaan linear dalam satu pemboleh ubah (i) Jika bilangan peserta yang tidak menerima
bagi setiap yang berikut. hadiah ialah satu pertiga daripada bilangan
Write a linear equation in one variable for each of the peserta yang menerima hadiah, cari nilai x.
following. If the number of participants who do not receive
(i) Satu nombor ditolak dengan 6, bakinya ialah prizes is one-third the number of participants who
3. receive prizes, find the value of x.
Subtract 6 from a number, its remainder is 3. (ii) Seterusnya, hitung bilangan peserta yang
(ii) Dua kali suatu nombor ditambah dengan 8, menerima hadiah.
hasilnya ialah 18. Hence, calculate the number of participants who
Twice a number added to 8, the result is 18. receive prizes.
(iii) Hasil bahagi suatu nombor dengan 12 ialah [4 markah / 4 marks]
5. Jawapan / Answer:
The quotient of a number and 12 is 5. (i) 1 + 2 + x = 1 (6x + 3)
[3 markah / 3 marks] 3
Jawapan / Answer: 3 + x = 2x + 1
3 + x – 1 = 2x + 1 – 1
(i) x – 6 = 3
(ii) 2x + 8 = 18 2 + x = 2x
x 2 + x – x = 2x – x
(iii) = 5 2 = x
12
x = 2
(ii) Bilangan peserta menerima hadiah
(b) Selesaikan: / Solve: Number of participants who receive prizes
3(6 – y) = 12 = 6(2) + 3
[3 markah / 3 marks] = 12 + 3
= 15

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