Page 7 - Steady Mate Tg1 - Book B

Matematik Tingkatan 1 Bab 2 Faktor dan Gandaan

H Tentukan faktor sepunya terbesar (FSTB) bagi setiap yang berikut. TP 3 ARAS S
Determine the highest common factor (HCF) for each of the following.

Kaedah pembahagian berulang / Method of repeated division
Contoh 1. 20, 48 2. 90, 108

8, 24 2 20 , 48 2 90 , 108
2 8 , 24 2 10 , 24 3 45 , 54
2 4 , 12 5 , 12 3 15 , 18
2 2 , 6 5 , 6
1 , 3
FSTB / HCF = 2 × 2 FSTB / HCF = 2 × 3 × 3
Ulang pembahagian sehingga tiada = 4 = 18
faktor perdana sepunya.
Repeat the division until no common
prime factors.
FSTB / HCF = 2 × 2 × 2
= 8

Contoh 3. 20, 50, 100 4. 18, 72, 144
15, 30, 45 2 20 , 50 , 100 2 18 , 72 , 144
3 15 , 30 , 45 5 10 , 25 , 50 3 9 , 36 , 72
5 5 , 10 , 15 2 , 5 , 10 3 3 , 12 , 24
1 , 4 , 8
1 , 2 , 3
FSTB / HCF = 3 × 5 FSTB / HCF = 2 × 5 FSTB / HCF = 2 × 3 × 3
= 15 = 10 = 18

Kaedah pemfaktoran perdana / Method of prime factorisation
Contoh 5. 16, 24 6. 30, 105
Tulis setiap
8, 12 nombor
sebagai hasil 16 = 2 × 2 × 2 × 2 30 = 2 × 3 × 5
8 = 2 × 2 × 2 darab faktor 24 = 2 × 2 × 2 × 3 105 = 3 × 5 × 7
12 = 2 × 2 × 3 perdananya. ↓ ↓ ↓ ↓ ↓
↓ ↓ Write each 2 × 2 × 2 3 × 5
number as a
2 × 2 product of its
prime factors. FSTB / HCF = 2 × 2 × 2 = 8 FSTB / HCF = 3 × 5 = 15
FSTB / HCF = 2 × 2 = 4

Contoh 7. 16, 32, 40 8. 30, 54, 90

12, 36, 60
16 = 2 × 2 × 2 × 2 30 = 2 × 3 × 5
12 = 2 × 2 × 3 32 = 2 × 2 × 2 × 2 × 2 54 = 2 × 3 × 3 × 3
36 = 2 × 2 × 3 × 3 40 = 2 × 2 × 2 × 5 90 = 2 × 3 × 3 × 5
60 = 2 × 2 × 3 × 5 ↓ ↓ ↓ ↓ ↓
↓ ↓ ↓ 2 × 2 × 2 2 × 3
2 × 2 × 3
FSTB / HCF = 2 × 2 × 2 = 8 FSTB / HCF = 2 × 3 = 6
FSTB / HCF = 2 × 2 × 3 = 12

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