Page 40 - PRE-U STPM CHEMISTRY TERM 1
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Chemistry Term 1  STPM

                        (iii)  The beryllium atom in BeCl  is 4 electrons short   (b)   H  +  H  +   H    – +           –              –
                                              2
                           of octet. Hence, it will combine with
                                           H
                                                                           N
                                                 H
                                              N
                                                                        N
                           two NH  molecules to achieve octet.  H  N  H  H  H  H  H  H  N  H      H H  N N  H   H  N           H  N
                                 3
                  5  (a)                (b)   H              H          H  H           H             H H           H              H
                              x x                  x x
                                                                       NH : Trigonal pyramidal (3 bond-pairs + 1 lone-pair)
                                  sp 3                 sp 3               3
                                                                          +
                              O                    N                   NH : Tetrahedral (4 bond-pairs)
                                                                          4
                                                                       NH  : Bent (2 bond-pairs + 2 lone-pairs)
                                                                          –
                         x         x x        x          x                2
                          •                    •        •
                        H                    H            H         (c)
                              x •                  x •          N            N                  P            P
                              H                    H
                                                           CI         CI CI        CI     CI         CI CI        CI
                    (c)         x   π  π  •
                             sp    •         x                    CI           CI             CI            CI
                           x                  x                        NCl : sp  hybridisation
                                                                          3
                                                                             3
                         H  •   C   x •  N    x                        PCl : sp  hybridisation
                                            sp                            3   3
                                                                       NCl  has a larger bond angle. N is more electronegative
                                                                          3
                                                                       than P, the bonding electrons will be closer to N in
                  6  (a)      sp 2        sp 2                         NCl  compared to P in PCl . Thurs, the bond-pair
                                                                          3
                                                                                           3
                                                                       repulsion in NCl  is stronger and pushed the bonds
                                                                                   3
                                      O                                further apart.
                                   +                              9  (a)  (i) BeCl  + 2NH  → BeCl (NH )
                            CH     N                                         2     3     2   3 2
                                3                                      (ii)
                                                                                       H     H
                         sp 3         O                                        CI         N
                                         –
                                   sp 3                                                       H
                    (b)  Trigonal planar                                            Be
                    (c)           –                                          H
                           C  N
                                                                               N          CI
                                                                             H     H
                    (d)  The carbon-nitrogen bond in CN  is a triple bond
                                               –
                        while that in the CH NO  is a single bond.
                                      3  2                             (iii)  BeCl : sp hybridisation
                                                                              2
                  7  (a)  Mixing of two or more non-equivalent atomic      BeCl (NH ) : sp  hybridisation
                                                                                      3
                                                                                  3 2
                                                                              2
                        orbitals to form a set of equivalent hybrid orbitals.
                                           3
                    (b)  (i)  Nitrogen undergoes sp   hybridisation.  (b)  (i)   P
                                          x x
                                                                                     H
                                                                            H
                                                                                H
                                           N
                                                                       (ii)  Ammonia. Nitrogen is more electronegative than
                                      x        x •
                                     H  •       H                          phosphorus. As a result, the bonding electrons
                                          x •                              in the N—H bonds are nearer to the nitrogen
                                           H
                                                                           atom than the phosphorus atom in PH . As a
                                                                                                       3
                                          3
                        (ii)  Carbon undergoes sp   hybridisation.         result, the three N—H bonds experience greater
                                                                           mutual repulsion which pushed them further
                                           H
                                           x •                             apart than the P—H bonds in PH .
                                                                                                  3
                                                                  10  (a)  H (g) + Cl (g) → 2HCl(g)
                                           C                             2     2
                                        x •   • x                   (b)   Boiling point
                                           x •
                                     Cl          Cl
                                                                            HF
                                           Cl
                                                                                       HI

                  8  (a)  In the reaction, NH  accepts a proton from another        HBr
                                     3
                                    +
                        NH  to form NH . Thus, one of the NH  molecule        HCI
                                                    3
                                    4
                          3
                        acts as a Bronsted base (proton acceptor) and the               M of HX
                        other a Bronsted-Lowry acid (proton donor).                      r
                                                                                                        363
         12 Answers.indd   363                                                                          3/26/18   4:06 PM
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