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Matematik Tambahan  Tingkatan 5  Bab 1  Sukatan Membulat

          5.  Tentukan sudut tercangkum, q dalam radian, di pusat bulatan diberikan jejari bulatan, j dan panjang lengkok,
             s bagi setiap bulatan yang berikut.
             Determine the angle subtended, q in radian, at the centre of the circle given the radius, j and the arc length, s for each of the
             following circles.   TP  3
     1          CONTOH                                          (a)

                                                                               7.2 cm

     BAB                                                                       6.1 cm  O

                             4.4 cm
                          P
                                  O

                                        Q
                             9.8 cm                                            7.2
                                                                     (2π – q) =
               Penyelesaian:                                                   6.1
                   q rad   panjang lengkok, s / arc length, s              q = 5.1 rad
                          =
                   2π rad               2πj
               Ini boleh dringkaskan kepada
               This can be simplified into
                    s
               q  =
                    j    9.8
                 (2π – q) =
                         4.4
                     q   = 4.06 rad

               (b)              4.8 cm                          (c)

                                                                                =
                                                                                              =
                                   O  3.2 cm                                         O
                                                                                1.8 cm

                                                                                    2.8 cm

                           4.8                                                 2.8
                    (2π – q) =                                       (2π – 2q) =
                           3.2                                                 1.8
                       q = 4.78 rad                                        q = 2.36 rad

               (d)                                              (e)                11.4 cm

                           =

                                    2.5 cm
                                 O                                                  O

                                      =
                                     3.2 cm
                             =
                                                                            6.3 cm      8.2 cm
                                                                         2πj = 6.3 + 8.2 + 11.4
                  (2π – q)  =  3.2                                          j = 4.12 cm
                     3     2.5                                                 11.4
                        q = 2.44 rad                                       q =   4.12
                                                                             = 2.77 rad



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