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Additional Mathematics SPM  Chapter 2  Quadratic Functions

   (c)  The graph of  f (x) intersects the  x-axis at two   This function has two equal roots and the graph
      different points, therefore f (x) = 0 has two different   touches the x-axis at one point.
      roots.
   (d)  The graph of f (x) does not intersect or touches the
      x-axis, therefore f (x) = 0 has no roots.

      Try Question 3 in ‘Try This! 2.3’
                                                      Try Question 4 in ‘Try This! 2.3’
              16
   Determine the types of roots for the following            17
   quadratic functions. Hence, sketch the position of the   Given that the quadratic function f (x) = x  + 2x + 1 – k
                                                                                   2
   graph of the function with respect to the x-axis.   intersects the x-axis at two different points. Find the
   (a)  f(x) = 3x  – 4x – 2                       range of values of k.
             2
 Form 4
   (b)  f(x) = –5x  + 3x – 1
              2
   (c)  f(x) = x  – 8x + 16                       Solution
            2
                                                  f (x) = x  + 2x + 1 – k
                                                        2
   Solution                                       a = 1, b = 2 and c = 1 – k
   (a)  f(x) = 3x  – 4x – 2
             2
      a = 3, b = –4, c = –2                       f (x) = 0 has two different roots when
                                                         b  – 4ac . 0

                                                          2
             b  – 4ac  = (–4)  – 4(3)(–2)          (2)  – 4(1)(1 – k) . 0
              2
                         2
                                                     2
                     = 40 . 0                         4 – (4 – 4k) . 0
      a = 3 . 0, therefore the graph of the function is in      4 – 4 + 4k . 0
      the shape of  .                                         4k . 0
      This function has two different roots and the            k . 0
      graph intersects the x-axis at two points.
                                                      Try Questions 5 – 6  in ‘Try This! 2.3’
                                                             18
                                                  Given that the quadratic function
                                                                     1
   (b)  f(x) = –5x  + 3x – 1                      f (x) = p x  + (p – 1)x + — does not intersect the x-axis.
              2
                                                        2 2
                                                                     4
      a = –5, b = 3, c = –1                       Find the range of values of p.
             b  – 4ac  = 3  – 4(–5)(–1)
                       2
              2
                     = –11  0                    Solution      1
                                                   2 2
      a = –5  0, therefore the graph of the function is   p x  + (p – 1)x + — = 0
                                                                4
                                                                      1
      in the shape of   .                         a = p , b = p – 1 and c = —
                                                      2
      This function has no real roots and the graph does              4
      not intersect the x-axis.                   f (x) = 0 does not have real roots when
                                                           b  – 4ac   0
                                                            2
                                                               1
                                                               
                                                   (p – 1)  – 4(p ) —    0
                                                             2
                                                       2
                                                               4
                                                     p  – 2p + 1 – p    0
                                                      2
                                                                 2
                                                           –2p + 1   0
                                                                1   2p
   (c)  f(x) = x  – 8x + 16                                     1
            2
      a = 1, b = –8, c = 16                                    —   p
                                                                2
                                                                     1
             b  – 4ac  = (–8)  – 4(1)(16)                       p  . —
              2
                         2
                     = 0                                             2
      a = 1 . 0, therefore the graph of the function is in   Try Questions 7 – 10  in ‘Try This! 2.3’
      the shape of  .
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