Page 21 - Hybrid PBD 2022 Tg 4 - Matematik

Matematik Tingkatan 4 Bab 2 Asas Nombor

(e) 56240 7 (f) 31022 4 (g) 24351 6
5 6 2 4 0 3 1 0 2 2 2 4 3 5 1
7 4 7 3 7 2 7 1 7 0 4 4 4 3 4 2 4 1 4 0 6 4 6 3 6 2 6 1 6 0
6 × 7 = 2 058 3 × 4 = 768 5 × 6 = 30
1
4
3
4. Tentukan nilai nombor bagi setiap yang berikut. SP 2.1.1 TP3
Determine the value of each of the following numbers.

(a) 221 3
1011 2
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Nombor 1 0 1 1 Nombor 2 2 1
Number Number
Nilai tempat 2 3 2 2 2 1 2 0 Nilai tempat 3 2 3 1 3 0
Place value Place value
0
1
2
(1 × 2 ) + (0 × 2 ) + (1 × 2 ) Nilai nombor (2 × 3 ) + (2 × 3 ) + (1 × 3 )
3
1
2
Nilai nombor + (1 × 2 ) Number value = 18 + 6 + 1
0
Number value = 8 + 0 + 2 + 1 = 25 10
= 11 10
(b) 323 4 (c) 1234 5
Nombor Nombor
Number 3 2 3 Number 1 2 3 4
Nilai tempat 2 1 0 Nilai tempat 3 2 1 0
Place value 4 4 4 Place value 5 5 5 5
(3 × 4 ) + (2 × 4 ) + (3 × 4 ) (1 × 5 ) + (2 × 5 ) + (3 × 5 )
1
2
1
2
3
0
Nilai nombor 0
Number value = 48 + 8 + 3 Nilai nombor + (4 × 5 )
= 59 10 Number value = 125 + 50 + 15 + 4
= 194 10
(d) 350 6 (e) 615 7
Nombor 3 5 0 Nombor 6 1 5
Number Number
Nilai tempat 6 2 6 1 6 0 Nilai tempat 7 2 7 1 7 0
Place value Place value
(3 × 6 ) + (5 × 6 ) + (0 × 6 ) (6 × 7 ) + (1 × 7 ) + (5 × 7 )
1
1
0
0
2
2
Nilai nombor = 108 + 30 + 0 Nilai nombor = 294 + 7 + 5
Number value Number value
= 138 10 = 306 10
(f) 1076 8 (g) 748 9
Nombor Nombor
Number 1 0 7 6 Number 7 4 8
Nilai tempat 3 2 1 0 Nilai tempat 2 1 0
Place value 8 8 8 8 Place value 9 9 9
(1 × 8 ) + (0 × 8 ) + (7 × 8 ) (7 × 9 ) + (4 × 9 ) + (8 × 9 )
0
1
2
1
2
3
Nilai nombor + (6 × 8 ) Nilai nombor = 567 + 36 + 8
0
Number value
Number value = 512 + 0 + 56 + 6 = 611 10
= 574 10
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02 Hybrid PBD Mate Tg4.indd 15 25/10/2021 2:23 PM