Page 10 - Top Class F5 - Mathematics (Chapter 2)
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Mathematics  Form 5  Chapter 2  Matrices


            10.  The product of matrix  A and identity matrix,  I, is the     14.  ad – bc is known as the determinant of matrix A and is
             matrix A itself.                                    written as |A|, that is |A| = ad – bc.
             Hasil darab suatu matriks A dengan matriks identiti, I, ialah matriks      ad – bc dikenali sebagai penentu bagi matriks A dan ditulis sebagai
             A sendiri.                                          |A|, iaitu |A| = ad – bc.
                               AI = IA = A
                                                                15.  If ad – bc = 0, then the inverse matrix, A  does not exist.
                                                                                                –1
                                                                                               –1
            11.  When multiply two matrices, A and B, if         Jika ad – bc = 0, maka matriks songsang, A  tidak wujud.
             Apabila mendarabkan dua matriks, A dan B, jika     16.  The simultaneous  linear  equations  can be solved  by
                              AB = BA = I,
              then B is the inverse matrix of A and A is the inverse      matrix method. Given
                                                                 Persamaan linear serentak boleh diselesaikan dengan kaedah
             matrix of B.                                        matriks. Diberi
             maka B ialah matriks songsang bagi A dan A ialah matriks songsang       ax + by = p
             bagi B.
                                                                                   cx + dy = q
            12.  The inverse matrix of A can be written as A .
                                                –1
             Therefore,                                          (a)  Write the simultaneous linear equations in the matrix
             Matriks songsang bagi A boleh ditulis sebagai A . Maka,   form.
                                             –1
                                –1
                                    –1
                             AA  = A A = I                           Tuliskan persamaan linear serentak dalam bentuk matriks.
                                                                                             p
                                                                                    a b x
                                                                                          
            13.  If matrix A =   a b  , then inverse matrix of A, A , can         c d y   =   q
                                                    –1
                         c d
                                                                                  x
             be found by the formula:                            (b)  Find the matrix    .
                         a b
                                                  –1                            y
             Jika matriks A =   c d  , maka matriks songsang bagi A, A , boleh   x
             dicari dengan rumus:                                    Cari matriks    .
                                                                              y
                            1     d  –b                                        x           d  –b p
                      –1
                     A  =              , ad – bc ≠ 0                           =   1        
                          ad – bc –c  a                                        y    ad – bc –c  a  q
          5.  Determine whether addition and subtraction can be performed on the following pairs of matrices.  PL 2
             Tentukan sama ada penambahan dan penolakan boleh dilaksanakan pada pasangan matriks berikut.
               Example                             14 16    5  7               (b)   –3 0   –6 5 9 
                                                                                          ,
                                                          ,
                                                            –8 9
                                                   1
                       2 8
                                                       7
               5 11   15 3                (a)                              10 5    2 1 20
                     ,
               4 –6
                                                   3 –4
                                                            6 –2
              Yes                                 Yes                             No
              Ya                                  Ya                              Tidak
              (c)  [3 15 9], [7 –1 ]          (d)  [23], [12]                      35   –9
                                                                               (e)     
                                                                                       ,
                                                                                        21
                                                                                   16
                  No                              Yes                             Yes
                  Tidak                           Ya
                                                                                  Ya
          6.  Solve each of the following.  PL 3
             Selesaikan setiap yang berikut.
               Example                             –2 11    6 –3                   15 1     3 –6
                                              (a)                                
                                                          +
                                                            2 –5
                                                       4
               –4 5 9
               16 7 8   –6 17 3               = 7  –2 + 6 11 + (–3)      (b)  –2 7  –  –5 4
                        –
                                                                                    8 11
                                                                                            12 14
                          3 –2 1
                                                                                    
                 –4 – (–6)  5 – 17 9 – 3           7 + 2  4 + (–5)                  15 – 3  1 – (–6)
              =   16 – 3  7 – (–2) 8 – 1          =  4 8                        = –2 – (–5)   7 – 4 
                                                                                      8 – 12
                 2 –12 6
              =   13  9  7                         9 –1                            12 7      11 – 14
                                                                                     
                                                                                  = 3    3
                                                                                     –4 –3
                a b     a ± p b ± q 
                     p q
                    ±
                          =
                           c ± r d ± s
                        s
                      r
                c d
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