Page 57 - Hybrid PBD 2021 Form 2 - Matematik
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Matematik   Tingkatan 2  Bab 3
                6.  Cari nilai bagi setiap yang berikut.   SP 3.1.3     TP3                                  E-pop Quiz
                  Find the value of each of the following.

                                                                     (a)  Diberi k =  y – 3h , cari nilai k apabila y = 4 dan
                                                                                  
                    Diberi a  = b  + c , cari nilai b apabila a = 13 dan     h = –7.
                           2
                                2
                                    2
                    c = 5.                                              Given k =  y – 3h , find the value of k when y = 4 and h = –7.
                                                                               
                    Given a  = b  + c , find the value of b when a = 13 and c = 5.
                         2
                            2
                               2
                                                                            
                      a  = b  + c 2  Gantikan nilai a dan c             k  = y – 3h
                      2
                           2

                                                                            
                     13  = b  + 5    dalam persamaan.                     = 4 – 3(–7)
                      2
                               2
                           2
                                    Substitute the values of a
                                    and c into the equation.
                     169 = b  + 25                                        = 4 + 21
                           2
                                                                            

                      b  = 169 – 25
                      2
                                                                            
                                                                          = 25

                           144
                      b =         Ungkapkan b sebagai perkara           = 5
                                    rumus dan selesaikan.
                        = 12        Express b as the subject of formula
                                    and solve it.
                                                                                       1
                                                                               1
                                      2
                    (b)  Diberi x =  3(2 – y ) , cari nilai x apabila y = –2 dan  (c)  Diberi   +  1  =  m , cari nilai k apabila h = 2 dan
                                    z
                                                                                   k
                                                                               h
                       z = –8.                                          m = 3.
                               3(2 – y )                                     1   1   1
                                    2
                       Given x =      , find the value of x when  y =  –2 and     Given   +   =  , find the value of k when h = 2 and m = 3.
                                  z                                          h     k    m
                       z = –8.
                                                                         1  +  1  =  1
                                 2
                       x =  3(2 – y )                                    h      k    m
                              z                                          1  +  1  =  1
                                    2
                         =   3[2 – (–2) ]                                2      k    3
                               –8                                             1  =  1  –  1
                                                                              k
                                                                                  3
                                                                                      2
                         =  3(–2)
                            –8                                                1  = –  1
                                                                              k
                                                                                   6
                         =  6
                           8                                                  k = – 6
                           3
                         =
                            4
                                                                                    
                    (d)  Diberi   4 + p   = t, cari nilai p apabila q = –2 dan     (e)  Diberi x = y² z, cari nilai z apabila x = 64 dan
                               5q
                                                                        y = 2.
                       t = –1.                                          Given x = y² z , find the value of z when x = 64 and y = 2.
                                                                                 
                            4 + p
                       Given      = t, find the value of p when q = –2 and t = –1.
                             5q                                           x = y² z
                                                                                
                        4 + p   = t                                       64 = 2² z
                                                                                
                         5q
                                                                          
                                                                         4 z = 64
                        4 + p   = –1
                        5(–2)                                               64
                                                                           z =
                                                                               4

                         4 + p  = –1(–10)                                    = 16
                               = 10
                            p  = 10 – 4                                   z = 16 2
                               = 6                                           = 256
                                                                30
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         Bab 3.indd   30                                                                                            9/3/21   5:13 PM
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