Page 60 - Hybrid PBD 2022 Form 4 Additional Mathematics
P. 60

Matematik Tambahan  Tingkatan 4  Bab 3 Sistem Persamaan
                3.  Selesaikan persamaan serentak berikut.           4.  Rajah di bawah menunjukkan kolam ikan ABCD
                  Solve the following simultaneous equations.           yang dikelilingi papan kayu sebagai laluan di
                                x(7y + x) = 16 − 34y 2                  sebuah kelong ikan.  KBAT  Mengaplikasi
                               2x − 14y = 4                             The diagram below shows a fish pond ABCD surrounded by
                                              [5 markah / 5 marks]      wooden boards as pathway in a fish kelong.
                   Jawapan / Answer :                                                  2(y – 1) m
                        x(7y + x) = 16 − 34y 2                                 P                      Q
                    7xy + x  + 34y  = 16 .......................                  A      y m     B
                               2
                         2
                    2x − 14y = 4                                                        Kolam ikan  x m   3x –      m
                                                                                                          7
                        2x = 14y + 4                                                    Fish pond         2
                         x = 7y + 2 ............................b                  D              C
                   Gantikan b ke dalam                                        S                      R
                             Penerbitan Pelangi Sdn Bhd. All Rights Reserved
                  Substitute b into 
                          7y(7y + 2) + (7y + 2)  + 34y  = 16            Diberi bahawa perimeter kolam ikan ABCD ialah
                                                  2
                                            2
                                                                                                           2
                  49y  + 14y + 49y  + 28y + 4 + 34y  − 16 = 0           16 m dan luas papan kayu ialah 29 m . Cari luas,
                   2
                               2
                                              2
                                                                                2
                                        2
                                    132y  + 42y − 12 = 0                dalam m , kolam ikan ABCD jika y  x.
                                                                        Given that the perimeter of the fish pond ABCD is 16 m and the
                                       22y  + 7y − 2 = 0                area of the wooden boards is 29 m . Find the area, in m , of the
                                           2
                                                                                                               2
                                                                                                 2
                                    (11y − 2)(2y + 1) = 0               fish pond ABCD if y  x.
                                                  y =   2 , y = −  1                                [5 markah / 5 marks]
                                                     11       2
                                                                                 KBAT
                   Apabila / When y =   2                                     Tip KBATKBAT
                                   11                                    Luas papan kayu = luas PQRS – luas ABCD
                        2
                  x = 7    + 2                                         Area of the wooded board = area of PQRS – area of ABCD
                        11
                      36
                     =                                                  Jawapan / Answer :
                      11                                                2x + 2y = 16
                   Apabila / When y = −  1                                   x + y = 8 ............................................
                                     2                                              7
                                                                               
                         1
                        
                  x = 7 −   + 2                                         2(y − 1) 3x −  2   − xy = 29 ................b
                         2
                     = −  3                                             Dari  / From : y = 8 − x ................c
                        2
                                                                        Gantikan c ke dalam b
                                                3
                  ∴ x =  36 , y =   2   dan / and x = −  , y = −  1     Substitute c into b
                        11     11               2      2                       2(8 − x − 1) 3x −  7   − x(8 − x) = 29
                                                                                         
                                                                                               2
                                                                                          7
                                                                                            
                                                                          
                                                                         2 21x −  49  − 3x  +  x  − 8x + x  − 29 = 0
                                                                                       2
                                                                                                    2
                                                                                2
                                                                                          2
                                                                            
                                                                                                    2
                                                                                2
                                                                           2 –3x  +  49  x –   49   − 8x + x  − 29 = 0
                                                                                    2
                                                                                          2
                                                                                               2
                                                                                           −5x  + 41x − 78 = 0
                                                                                     2
                                                                            −41 ±  − 4(−5)(−78)
                                                                                   41
                                                                        x =
                                                                                    2 (−5)
                                                                        x = 3 atau / or x = 5.2
                                                                        Apabila / When x = 3
                                                                        y = 8 − 3
                                                                          = 5
                                                                        Apabila / When x = 5.2
                                                                        y = 8 − 5.2
                                                                          = 2.8
                                                                        Maka, / Thus, x = 3, y = 5
                                                                        Luas kolam ikan ABCD / Area of the fish pond ABCD
                                                                        = 3 × 5
                                                                        = 15 m 2
              © Penerbitan Pelangi Sdn. Bhd.                      42


         03 Hybrid PBD Mate Tambahan Tg4.indd   42                                                                29/09/2021   3:30 PM
   55   56   57   58   59   60   61   62