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Mathematics Term 2  STPM  Chapter 2 Differentiation
                                             –1
               Derivative of arc cos x (cos  x)
                              –1
               Let      y  = cos x
                       x  = cos y
                      dx
                          = –sin y
                      dy
                      dy       1
                          = –
                      dx     sin y
                       2
                                 2
               but  sin y  = 1 – cos y
                          = 1 – x 2
                      dy         1
                  ∴       = –
                      dx       (1 – x )
                                    2
                                                                                                            2
                          d               1
                               –1
               Hence,       (cos x) = –
                         dx             (1 – x )
                                             2
                                             –1
               Derivative of arc tan x (tan x)
               Let      y  = tan x
                              –1
                       x  = tan y
                              2
                      dx   = sec y
                      dy
                      dy     1
                          =
                              2
                      dx    sec y
                          =    1
                                 2
                           1 + tan y
                          =   1
                           1 + x 2

                                –1
               Hence,     d   (tan x) =   1
                          dx          1 + x 2

               Rules of differentiation

               Differentiation of sums and differences of functions
               Consider two functions of x, p(x) and q(x), and let f(x) = p(x) + q(x).
               From the derived definition,
                        d              [p(x + x) + q(x + x)] – [p(x) + q(x)]
                           [f(x)]  =   lim
                       dx         x → 0              x
                                       [p(x + x) – p(x)] + [q(x + x) – q(x)]
                                 =   lim
                                  x → 0              x
                                       p(x + x) – p(x)     q(x + x) – q(x)
                                 =   lim             +   lim
                                  x → 0     x        x → 0     x
                                  d          d
                                 =    [p(x)] +    [q(x)]
                                  dx        dx

                        d          d         d
               Hence,      [f(x)] =    [p(x)] +    [q(x)]
                        dx        dx         dx


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       02 STPM Math(T) T2.indd   25                                                                 02/11/2018   12:43 PM
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