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Mathematics Term 2  STPM  Chapter 2 Differentiation
                        d           (x + x)  – x 3
                                          3
                          x   =   lim
                           3
                       dx     x → 0    x
                                      2
                                                   2
                            =   lim  [3x  + 3x x + (x) ]
                              x → 0
                            = 3x 2
                                3 – 1
                            = 3x
                       d            (x + x)  – x –1
                                          –1
                          –1
                          x   =   lim
                      dx      x → 0     x
                            =   lim   –   1
                              x → 0  x(x + x)
                                1
         2                  = –  x 2
                            = –x –2
                            = –1(x –1 – 1 )
             Hence,
                           n
                        d   x   = nx n – 1 , n  R.
                       dx
                 Example 3

              Differentiate with respect to x.
              (a)  x –3                                   (b)    x
              (c)  –5x 4                                  (d)  3
                                                              x 6
              Solution:           (a)  Let   y  = x –3
                                          dy                     3
                                                           –4
                                              = –3x –3 – 1  = –3x  = –
                                          dx                     x 4
                                  (b)  Let   y  =   x  = x — 1 2
                                          dy    =   1   x — – 1   =   1   x  =   1
                                                   1
                                                             1
                                                   2
                                                            –—
                                                              2
                                          dx    2        2       2  x
                                  (c)  Let   y  = –5x 4
                                          dy   = –5(4x 4 – 1 ) = –20x 3
                                          dx
                                  (d)  Let   y  =   3 6   = 3x  – 6
                                                x
                                          dy   = 3[–6x –6 – 1 ] = –18x  = –  18
                                                               –7

                                          dx                        x 7
                 Exercise 2.2

             Find the derivatives of the following functions with respect to x.


                                                                    5
               1.  5           2.  3x          3.  –4x         4.  x           5.   x –4
                   1
                  —
                                                    x
                                                     3
               6.  x           7.  x           8.            9.   1         10.   3 x 2
                                   –1
                   3
                                                                     x
                                                                      3
                                    10
                   –3
              11.  5x         12.  7x         13.   5         14.   7  x      15.   –2
                                                   4x 4            8               x 8
              20
       02 STPM Math(T) T2.indd   20                                                                 02/11/2018   12:43 PM
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