Page 35 - Unit2.docx

vertical piles laying on axis b and c

2
2 
2 
∑ ( 0.5 2 + 0.5 2) = 2.0 m

2
∑ = vertical and raking piles = 2.07 + 2.0 = 3.07 m

© It's Engg. Life
5. Calculate load distribution on individual piles:

Q ⇒ P V =


P r = P v cosα = 232 0.98 = 227kN


H ⇒ P r = ±

M ⇒

PILE ar br bv cv cr dr

Q (kN) 227 227 232 232 227 227

H (kN) -85 -85 0 0 85 85



-85 (-0.3 0.98) = 25 -50*** 43** -43** 50*** -25
M =

∑ force on Pi (kN) 267 92 275 289 323 287

 
a r = -85 (-0.3 0.98) = 25

 
b r = -85 (0.6 0.98) = -50.0***


b v 2, b v 3 = -85 (-0.5) = 42.5**


c v 2, c v 3 = -85 (0.5) = -42.5

where:

a r , b r , b v , c v , c r , d r represent raking and vertical piles on respective axis.

3.3.2 Example on installation error

Until now we have been calculating theoretical force distribution on piles. However during