Page 220 - Engineering Mathematics Workbook_Final
P. 220

Numerical Methods

            59.    Consider the first order initial value                (III) Simphson’s Rule
                                         −
                   problem  y = +     2x x ,  ( ) 0 = ,                  (IV) Runge-Kutta
                                             2
                              1
                                  y
                                                        1
                                                y
                              )
                         x
                   (0     with exact solutions
                                                                         Choose the correct set of
                                  x
                    y ( ) x =  x +  2  e . For x = 0.1, the              combinations.
                   percentage difference between the
                   exact solution and the solution                       (a) P – II, Q – I, R – III, S - IV
                   obtained using a single iteration of                  (b) P – I, Q – II, R – IV, S – III
                   the second-order Runge-Kutta
                   method with step-size h = 0.1 is.                     (c) P – IV, Q – III, R – II, S – I

                            [GATE 2016 – EC – SET-3]                     (d) P – II, Q – I, R – IV, S – III

                                           du                                              [GATE 2017 (CH)]
            60.    Consider the equation       =  3t +  2  1
                                           dt                     63.    Variation of water depth (y) in a
                   with u = 0.1 at t = 0. This is                        gradually varied open channel flow is
                   numerically solved by using the                       given by the first order differential
                   forward Euler method with a step                      equation
                   size.  t   =  2. The absolute error in
                                                                                            10
                   the solution at the end of the first                        dy      1 e   3  ln y
                                                                                         −
                   time step is __________.                                       =            −
                                                                                         −
                                                                               dx   250 45e     3ln y
                      [GATE 2017 – CE – SESSION-1]
                                                                         Given initial combination y (x = 0) =

            61.    Match the problem type in Group – 1                   0.8 m. The depth (in m, up to three
                   with the numerical method in Group                    decimal places) of flow at a
                   – 2                                                   downstream section at x = 1m from
                                                                         one calculation step of Single Step
                   Group – 1                                             Euler Method is _______


                   (P) System of linear algebraic                    [GATE 2018 ( ME – Morning Session)]
                   equations
                                                                  64.    An explicit forward Euler method is
                   (Q) Non-linear algebraic equations
                                                                         used to numerically integrate the

                   (R) Ordinary differential equations                   differential equation   dy  =  y  using a
                                                                                               dt
                   (S) Numerical integrations
                                                                         time step of 0.1. With the initial

                   Group – 2                                             condition y(0) = 1, the value of y(1)
                                                                         computed by this method is
                   (I) Newton-Raphson                                    __________ (correct to two decimal

                   (II) Gauss-seidel                                     places).




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