Page 47 - Engineering Mathematics Workbook_Final
P. 47

Calculus

                                                                           1                        1
                (a)                      (b)                         (a)                      (b)
                     2                                                    5015                    15015

                                             −                              1                       1
                (c) -                   (d)                          (c)                      (d)
                                               2                           5005                    5001
                                                                                        / 2
                                 
                                                                                                   
                                 
            275.  The value of  e   − 5x 4 x dx is ______         280.  The value of       cot   d  is ______
                                 0                                                      0
                                                                                                  
                    3                       2                       (a)                      (b)
                (a)                      (b)                                2                       3
                      2                        3
                                                                                                  
                                                                    (c)                      (d)
                (c)                      (d)                               2                        4
                      3                       2
                                                                                          x
                                     a
            276.  The value of      x  dxis _________           281.  The value of    1 x 6  dx  is ________
                                                                                          +
                                  0 a x                                                0
                        a                       a + 1                                              
                (a)                      (b)       a+                 (a)                      (b)
                    (ln a ) a                (ln a )  1                     3                      3 3


                         a                     a + 1                                                
                (c)        a+            (d)                          (c)                      (d)
                     (ln a )  1              (ln a ) a                       2                     2 2
                                                                                          4   +  5 )
                    1                                                                     x  ( 1 x
                          −
            277.    x 6  1 x dx =  2                             282.  The value of      (1 x ) 15  dx is _____
                                                                                             +
                    0                                                                   0
                                                                        1                        1
                (a)                      (b)                          (a)                      (b)
                    256                      128                          5005                     5001

                                           3                             1                        1
                (c)                      (d)                          (c)                      (d)
                     512                     512                          1001                    10001
                                 1   x 6                          283.  The  length  of  the  arc  y =  x 3/ 2 , z =  0
            278.  The value of     −  2  dx =
                                 0 1 x                                from  (0, 0, 0) to (4, 8, 0) is ________
                                            3                            8     3/ 2
                (a)                      (b)                          (a)  ( 10     +  ) 1
                    32                       32                           27

                     5                                                    8     3/ 2
                (c)                      (d)  0                       (b)  ( 10     −  ) 2
                     32                                                   27

                                 1                                         8     3/ 2  −
                                 
            279.  The value of  x   4 (1 5x dx−  ) 5  is _____        (c)  ( 10        ) 1
                                                                          27
                                 0


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