Page 174 - Robot Design Handbook ROBOCON Malaysia 2019

2.5 Calculating the Height for Launching the Shagai

Figure 24: Shagai launching

Refering to the rule which was given in ROBOCON competition 2019, the Shagai
must be able to travel 2 m on the horizontal displacement

1
2
h =⁡u t + a t (1)
y
y
2
2
Given that h = 0.28 cm, ay = 9.81 m/s (since moving downward) and uy = 0 m/s, thus,
1
2
0.28 =⁡ (9.81)t
2
Since the horizontal and vertical times are constant and y horizontal projectile motion can
2
be assumed as 0 m/s

1 x
2
x =⁡u t + a t and t = u x ⁡ (2)
x
x
2
Substitute (2) into (1)
1 x 2 1 2
2
h =⁡ a ( ⁡) 0.28 =⁡ (9.81)( ⁡) ux = 8.37 m/s
y
2 u x 2 u x

After that, apply Newton’s Second law of motion, F = ma
Since the piston force which has been determined is 188 N and measured the Shagai

weight is 772 g and ux which has been determined above is 8.37 m/s. Therefore, substitute

all the related parameters into the equation of Newton’s second law of motion.

F 188
2
a =⁡ a =⁡ a = 243.52 m/s
m 0.772

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