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Chemistry Form 4 • MODULE

(f) Draw the a labelled diagram to show the set-up of apparatus used Step II and Step III.
Lukiskan gambar rajah berlabel untuk menunjukkan susunan alat radas yang digunakan dalam Langkah II dan Langkah III.

Excess of Filter paper Copper(II) sulphate solution
copper(II) oxide

Heat
Copper(II) sulphate
solution

(g) Can copper powder replace copper(II) oxide in the experiment? Explain your answer.
Bolehkah serbuk kuprum digunakan untuk menggantikan kuprum(II) oksida dalam eksperimen ini? Terangkan jawapan anda.
Cannot. Copper is less electropositive than hydrogen in the electrochemical series, copper cannot displace hydrogen

from the acid.

(h) Name other substance that can replace copper(II) oxide to prepare the same salt. Write a balance chemical equation
for the reaction that occur.
Namakan sebatian lain yang dapat menggantikan kuprum(II) oksida dalam penyediaan garam yang sama. Tuliskan persamaan kimia
yang seimbang bagi tindak balas yang berlaku.
Substance / Garam larut : Copper(II) carbonate
Balance equation / Persamaan seimbang : CuCO + H SO CuSO + H O + CO 2
2
4
3
2
4
3 The diagram below shows the flow chart for the preparation of lead(II) nitrate and lead(II) sulphate through reaction I
and II.
Rajah di bawah menunjukkan carta aliran bagi penyediaan plumbum(II) nitrat dan plumbum(II) sulfat melalui tindak balas I dan II.
Reaction I Reaction II
Lead(II) carbonate Tindak balas I Lead(II) nitrate Tindak balas II Lead(II) sulphate
Plumbum(II) karbonat Plumbum(II) nitrat Plumbum(II) sulfat

(a) (i) What is meant by salt?
Apakah maksud garam?
Salts are ionic compounds produced when hydrogen ion from acid is replaced with metal ion including

ammonium ion.
(ii) Based on the flow chart above, classify the above salt to soluble salt and insoluble salt.
Berdasarkan carta aliran di atas, kelaskan garam-garam tersebut kepada garam larut dan garam tak larut.

Soluble salt / Garam larut : Lead(II) nitrate
Insoluble salt / Garam tak larut : Lead(II) carbonate, Lead(II) sulphate
(b) (i) Describe how lead(II) nitrate solution is obtained in reaction I.
Terangkan bagaimana larutan plumbum(II) nitrat diperoleh daripada tindak balas I.
– Measure and pour 50 cm of 1 mol dm nitric acid in a beaker.
–3
3
-3
3
Sukat sebanyak 50 cm asid nitrik 1 mol dm dan tuangkan ke dalam bikar.
– Lead(II) carbonate powder is added to the acid in the beaker until excess .
Serbuk plumbum(II) karbonat ditambahkan kepada asid di dalam bikar sehingga berlebihan .
– Stir the mixture with a glass rod.
Campuran tersebut dikacau dengan rod kaca.
– The mixture in the beaker is filtered.
Campuran dituraskan.
– The filtrate is lead(II) nitrate solution .
Hasil turasan ialah larutan plumbum(II) nitrat.

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