Page 10 - Modul A+1 Matematik Tambahan Tingkatan 4
P. 10

(d)  Dalam rajah di bawah, suatu fungsi v memetakan x   (e)  Diberi f (x) =  x – 2 , x ≠ 3 dan g(x) =   3   , x ≠ 2, cari
                          kepada y dan fungsi w memetakan y kepada z.                 x – 3             x – 2
                          In the  diagram below, a function  v  maps x  to  y  and a   f (6) dan gf (6).
                                                                                      2
                                                                             2
                          function w maps y to z.                          Given f (x) =  x – 2 , x ≠ 3 and g(x) =   3   , x ≠ 2, find f (6)   BAB 1
                                                                                                                    2
                                                                                    x – 3            x – 2
                                  x            y           z               and gf (6).
                                                                                 2
                                               9
                                         v           w
                                                                             2
                                 8                          k              f (6) = ff (6)
                                                                               = f   6 – 2 
                                                                                   6 – 3
                                                                                   4
                                                                               = f   
                                                                                   3
                       ©PAN ASIA PUBLICATIONS
                          Diberi v(x) = 1 + x dan w(x) = x  – 1, cari            4
                                                   2
                          Given v(x) = 1 + x and w(x) = x  – 1, find           =  3  – 2
                                                 2
                          (i)  nilai k,                                          4  – 3
                              the value of k,                                    3
                          (ii)  fungsi yang memetakan x kepada z.                –  2
                              the function that maps x to z.                   =   3
                                                                                 –  5
                                                                                  3
                          (i)  k = 9  – 1 = 80                                 =  2
                                  2
                                                                                 5
                                                                                    2
                          (ii)  wv(x) = w(1 + x)                           gf (6) = g  
                                                                              2
                                                                                    5
                                          2
                                   = (1 + x)  – 1                                   3      7
                                            2
                                   = 1 + 2x + x  – 1                            =  2   = –1 8
                                         2
                                   = 2x + x                                       5  – 2
                  2.  Selesaikan setiap yang berikut.
                    Solve each of the following.  TP 3
                                                                                                              5
                      Contoh/Example                   (a)  Diberi f : x → x + 6 dan   (b)  Diberi fungsi m : x →  , x ≠ 0
                                                          gf : x → x  – x + 1, cari fungsi                    x
                                                                  2
                      Diberi f : x → x + 1 dan            g(x).                            dan nm : x → 10x, cari
                      fg : x → 2x  + x – 1, cari fungsi g(x).  Given f : x → x + 6 and     Given the function m : x →  , x ≠ 0
                                                                                                               5
                               2
                      Given f : x → x + 1 and             gf : x → x  – x + 1, find the function               x
                                                                  2
                      fg : x → 2x  + x – 1, find the function   g(x).                      and nm : x → 10x, find
                               2
                      g(x).                                                                (i)  n(x),
                                                                                           (ii)  nilai x apabila mn(x) = 12.
                                                          g[f (x)] = x  – x + 1                the value of x when mn(x) = 12.
                                                                   2
                        f [g(x)]  = 2x  + x – 1           g[x + 6] = x  – x + 1
                                 2
                                                                    2
                       g(x) + 1  = 2x  + x – 1                                             (i)   n[m(x)] = 10x
                                 2
                                                                                                    5
                          g(x) = 2x  + x – 1 – 1          Katakan    x + 6 = y                    n    = 10x
                                 2
                          g(x) = 2x  + x – 2                           x = y – 6                    x
                                 2
                                                          Gantikan                             Katakan   5   = y
                                                                                                         x
                                                          g(y) = (y – 6)  – (y – 6) + 1                  x  =  5
                                                                     2
                                                          g(y) = y  – 12y + 36 – y + 6 + 1                   y
                                                                 2
                                                          g(y) = y  – 13y + 43                 Gantikan
                                                                 2
                                                          g(x) = x  – 13x + 43                         5
                                                                 2
                                                                                               n(y) = 10  
                                                                                                       y
                                                                                               n[y] =  50
                                                                                                     y
                                                                                               n(x) =  50
                                                                                                     x
                                                                                           (ii)    mn(x) = 12
                                                                                                   5   = 12
                                                                                                  50
                                                                                                   
                                                                                                   x
                                                                                                 5 ÷  50  = 12
                                                                                                    x
                                                                                                 5 ×   x   = 12
                                                                                                   50
                                                                                                    x = 120
                                                                   7



         01_Modul A+ MateTam Tg4.indd   7                                                                        08/10/2021   11:18 AM
   5   6   7   8   9   10   11   12   13   14   15