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MODUL • Fizik TINGKATAN 5

Latihan / Exercise

1 Polonium-210 mengalami reputan alfa untuk menjadi plumbum-206. Persamaan reputan ialah
Polonium-210 undergoes alpha decay to become plumbum-206. The equation for the decay is:
210 Po 206 Pb + 4 He + Tenaga / Energy
82 84 2

Maklumat tambahan: / Additional information:

210
210
Jisim Po / Mass Po = 209.982 a.m.u.
82 82
206
206
Jisim Pb / Mass Pb = 205.969 a.m.u.
84 84
4
4
Jisim He / Mass He = 4.004 a.m.u.
2
2
1 a.m.u. = 1.66 × 10 kg
–27
c = 3 × 10 m s –1
8
Menggunakan persamaan dan maklumat di atas, kirakan
Using the equation and the information above, calculate
(a) cacat jisim / the mass defect
(b) tenaga dibebaskan / the energy released
Penyelesaian / Solution
206
210
4
(a) Cacat jisim / Mass defect = Jisim / Mass Po – (Jisim / Mass Pb + Jisim / Mass He)
84
2
82
= 209.982 a.m.u. – ( 205.969 a.m.u. + 4.004 a.m.u.)
= 0.009 a.m.u.
(b) E = mc 2
= (0.009 × 1.66 × 10 ) kg × (3 × 10 m s )
-1 2
8
–27
= 0.1345 × 10 J
–11
= 1.345 × 10 –12 J
2 Dalam ujian letupan nuklear, 0.5 g uranium telah ditukar kepada tenaga dalam masa 0.05 µs. Berapakah kuasa dalam letupan
nuklear?
[Halaju cahaya = 3.0 × 10 m s ] UNIT 5
–1
8
In a test of nuclear explosion, 0.5 g of uranium has been converted to energy in 0.05 µs. What is the power of the nuclear explosion?
[Speed of light = 3.0 × 10 m s ]
–1
8
UNIT 5
Penyelesaian / Solution
E
Kuasa / Power, P = t
mc 2
=
t
(0.5 × 10 ) kg × (3.0 × 10 m s )
8
–3
-1 2
=
(0.05 × 10 ) s
–6
= 9 × 10 W
20
Video

Tenaga Nuklear
Nuclear Energy
https://goo.gl/m6TDGq

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