Page 125 - Lecture Notes DCC3113
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Example 8.2
               Contoh Soalan :

               A 2-phase signal is to be installed at the following junction. Q flow is shown in the figure and Saturation
               flow is shown in the following table.

                                                       N
                                                                  416

                                         W                               E

                                         780


                                                                   1000


                                                                   356
                                                        S

                                                Table 8-5:  Saturation Flow Table

                     Direction/Cabang         North/Utara     South/Selatan      East/Timur        West/Barat
               Saturation Flow/Aliran Tepu, S
                        (pcu/hr)                1950              1950             2250              2250

               Intergreen/ Masa antara hijau    =    4 sec
               Amber/ Masa kuning          =       3 sec
               Lost time /Masa terhilang    =      2 sec

               a)     Determine the total lost time, L
               b)     Determine the optimum cycle time, CO
               c)     Determine the actual green time for each phase.
               d)     Sketch the traffic signal diagram

               Solution:

                    Direction/Cabang         North/Utara    South/Selatan     East/Timur      West/Barat
               Actual flow/Aliran Sebenar (q)   416              356             1000             780
                         pcu/h
               Saturation Flow/Aliran Tepu,     1950            1950             2250            2250
                       S (pcu/hr)
                        y  =  q/s              >0.21<           0.18            >0.44<           0.35

               a.     Select maximum value,
                      y (E/W)              =       0.44
                      y (N/S)              =       0.21
                             Y             =       ∑  y maximum
                                           =       0.44  +  0.21
                                           =       0.65  ≤   0.85 (OK)

               Total lost time per cycle /Jumlah masa terhilang, L    =   ∑ ℓ   +  ∑( I – a)

               Where,
               Intergreen time between phases /Masa antara hijau, (I)                  =      4 s
               Amber time /Masa kuning, (a)                                            =      3 s
               Drivers reaction time at the beginning of green per phase /Masa terhilang, (ℓ)   =   2 s


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