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Document Title
Fundamentals of Stress and Vibration 2. Engineering Mechanics Chapter
[A Practical guide for aspiring Designers / Analysts]

šƒ’Ž‡ ͵ǣ ƒ –”ƒ‹ ‹• ‘˜‹‰ †‘™ •‘—–Š ƒ– ƒ Žƒ–‹–—†‡ ‘ˆ ǮɅǯǡ ƒ• •Š‘™ ‹ ȏ ‹‰ ʹǤ͹͵ȐǤ ‹† –Š‡
‘”‹‘Ž‹• ˆ‘” ‡ ‡š’‡”‹‡ ‡† „› –Š‡ –”ƒ‹Ǥ

[Fig 2.73: train travelling down south at a latitude 'θ']

Solution: the Coriolis force is given by:

Coriolis force = 2m v × ω (this expression is for reactive Coriolis force, which is the exact
opposite to active Coriolis force [2m ω × v ]. This is similar to the relation between centrifugal
and centripetal acceleration)

The ‘x-component’ of the velocity is perpendicular to the rotation vector of the earth. Therefore,
the Coriolis force experienced by the train is given by:

[(Coriolis force) train = 2m vsin θ i × ω j = 2m v sinθ ω k

QP No. SSC/Q4401, Version 1.0, NSQF Level 7, Compliant with Aero and Auto Industries, P
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