Page 30 - FOCUS KSSM TG 4 MATEMATIK TAMBAHAN

Matematik Tambahan Tingkatan 4 Jawapan

(f) 1 1 14. p = 2, q = 3
f(x) 31. (a) h = , k = – 6
3
2 1 2
–
, 0 (b) 2 4 15. (a) Nilai minimum f(x) = 7 apabila x = 1
x f(x) (b) f(x)
0 1
x = –
2
x 9
–3 –2 0 3 4
(1, 7)
–9
3
x = – x
2 0 1
(g) f(x) –6 16. (a) p = 4, k = 16
(b) x = 4
1 2 2 1 2 17. (a) p = –1
3 1
, –
1
–
1
, –6–
–
2 4
4
(b) q = –2
x 18. 0.6
0 1 2 (c) f(x) = – x – 1 2 + 6 1 4 19. x > 1
1
2
2
1
2
32. (a) K(x) = – (x – 40) + 600
2
(b) (i) 40 Kertas 2
3 1
x = – (ii) RM600 seminggu 1. (a) p . –
–2 2 1 2
33. (a) H(x) = (x – 16) + 436
2
1
4 (b) p = 7 , q = – 4
(b) (i) 16 2
(ii) RM436
2. Tidak boleh. Lebar kotak kurang daripada diameter tiga
3
2
(h) f(x) 34. (a) A = 12x – x bar coklat (15 cm).
2
(b) (i) x = 4 m, y = 6 m 3. 32 cm dan 44 cm
(ii) 24 m 2 4. RM18.75
x
0 3 3 35. (a) x = 15 m, y = 20 m 1 2
4 1 2 (b) 600 m 2 5. (a) f(x) = – 4 x – 2 2
1
, – –
–
4
(b) f(x)
Praktis SPM 2 1 2 1 2
–
, 0
Kertas 1
–3 1. (a) 5 (b) 2 0 x
x = – 3 2
4 2. x – 6x – 6 = 0
2
3. 24x + 8x – 3 = 0
4. x , –1 atau x . 7 x = – 1
3 25 5. m = –2, n = 3 2
30. (a) p = – , q = –1
2 8 9
6. (a) h = 1 (b) k =
(b) (i) –1, 4 2
(ii) 7. 3 : 2  2 6. (a) h = 4, k = –9
2
8. k , 4 (b) (–1, 0) dan (5, 0)
2 1 2 9. (a) m = – 4, p = 8
f(x) 3 1 7 f(x)
, 6 –
–
4
(b) x + 3x – 10 = 0
2
4 10. (a) m = –5, n = –12 x = 2
1
(b) k , –15
3 8 1 0 x
x = – 11. x < –15 atau x > –1 5
2 3
1
1
12. (a) 3 , 24 1 2 2 (b) 0 , x , 7
2
x
–1 0 4 1 1 1
1
13. (a) 4 , –6 4 2 (b) x = 4 2
2
(c) 2 , x , 7 –5
(2, –9)
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