Page 29 - FOCUS KSSM TG 4 MATEMATIK TAMBAHAN
P. 29
Matematik Tambahan Tingkatan 4 Jawapan
(c) f(x) (f) f(x)
2 1 2
3
–
5 , 0
x = –
2
8 0 x
–9
3
x = –
x 2
0 1 4
(g) f(x)
3 1
–
, –
1 2 1 2
5
9
–
2 4
, – –
2
2
x
0 1 2
(d) f(x)
x = –3 3
x = –
9 –2 2
(h) f(x)
x
0 3 3
–
, – –
x 4 1 2
4
0
(–3, 0)
–3
3
x = – 4
(e) f(x)
(–1, 9) 3 25
30. (a) p = – , q =
2 8
(b) (i) –1, 4
(ii)
2 1 2
f(x) 3 1
, 6 –
–
4
5
x = –1 4
3
x = –
2
x
0 x
5 1 0
– – – –1 4
2 2
232

