Page 22 - Focus SPM KSSM F4 2020 - Chemistry
P. 22

Chemistry Form 4  Chapter 3 The Mole Concept, Chemical Formula and Equation
                                                  Ionic compound:           Iron(III) chloride
        ①   Based on its name, write the formula of
           the cation followed by the formula of
           the anion.                                              Fe 3+         CI -


        ②   Determine the number of cations and       1 Fe ion              3 CI ions
                                                                                -
                                                          3+
           anions by balancing the positive           Total positive charges  Total negative charges
           charges and negative charges.
                                                      = 1(+3)               = 3(-1)
                                                      = +3                  = -3
        ③   Write the number of cations and anions
           as subscript numbers.                                  Formula : FeCI
                                                                             3
                           Figure 3.12  Steps in constructing the formula of an ionic compound


                                                                      SPM Tips
      EXAMPLE 3.23
  Chapter
 3     Write the formula of sodium sulphate.          Students need to memorise the formulae of cations
                                                      and anions. If not, the chemical formulae cannot be
       Solution                                       constructed correctly.
       Ionic compound:  Sodium  sulphate
                                                       3.  When polyatomic ions such as OH , NO ,
                                                                                       –
                                                                                            –
                                                                                            3
                                                                     +
                                                            2-
                   Na +         SO  2–                   SO  and NH  are involved, brackets are used
                                  4                         4       4
                                                         to show the number of ions in the formula. See
                                                         Figure 3.12.
            +
        2 Na ions:          1 SO 4 2–  ions:
        Total positive charges  Total negative charges       Mg(OH)      Fe(NO )     (NH ) SO
        = 2(+1)             = 1(-2)                                2           3 3       4 2  4
        = +2                = -2                           The brackets   The brackets   The brackets
                                                          show there are  show there are  show there are
                                                            2 groups of   3 groups of   2 groups of
                  Formula : Na SO                             OH –         NO  –        NH  +
                            2  4                                              3            4
                                                         Figure 3.13  Brackets are used to show the number
                                                                  of polyatomic ions
       SPM    Highlights
       The formula of calcium chloride and potassium bromate(V) are CaCl  and KBrO . What is the formula of calcium
                                                                   3
                                                           2
       bromate((V)?
       Examiner’s tip
       From the formula of KBrO , 1 ion K  is needed to balance 1 bromate((V) ion. So, it can be deduced that the formula
                                 +
                          3
       of bromate(V) ion is BrO . -
                         3       Ionic compound:   Calcium  bromate(V)

                                            Ca 2+        BrO 3  –


                                 1 ion Ca :             2 ion BrO :
                                                                –
                                       2+
                                                                3
                                 Total positive charges  Total negative charges
                                 = 1(+2)                = 2(-1)
                                 = +2                   = -2
                                            Formula : Ca(BrO )
                                                          3 2


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