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Matematik Tambahan  Tingkatan 5  Bab 1  Sukatan Membulat

                        Praktis SPM                                               1                      Praktis Ekstra
                                                SPM
                                                                                                         SPM 1
           1

           BAB  Kertas   1                                              Diberi bahawa panjang perentas ialah 8 cm, cari
                                                                        Given the length of the chord is 8 cm, find
                1.  Rajah di bawah menunjukkan pandangan hadapan        (a)  sudut q, dalam radian,
               Buku   sebahagian mural berbentuk segi empat tepat           the angle q, in radians,
               Teks  10 m  × 8 m.  ABP dan  DCP adalah dua sektor       (b)  luas rantau berlorek itu.
               ms. 8-18                                                     the area of the shaded region.
                   serupa berpusat P dan BC adalah selari dengan FE.
                   Bahagian berlorek perlu dicatkan.                    (a)  8  = 15  + 15  – 2(15)  kos q
                                                                             2
                                                                                  2
                                                                                               2
                                                                                       2
                   The diagram below shows a front view of a rectangular
                                                                                     2
                                                                                           2
                   mural of  10 m  × 8 m. ABP and DCP are two similar        kos q =   15  + 15  – 8 2
                   sectors with centre P and BC is parallel to FE. The shaded        2(15)(15)
                   region needs to be painted.                                 q = 30.93°
                                F     10 m    E
                                                                            30.93°  × 2π = 0.54 rad
                                    B  4 m  C                                360°
                                               8 m
                                                                        (b)  Luas tembereng
                                                                            Area of segments
                                                                                           1
                                A      P      D                             =  1  (15) (0.54)−  (15)  sin30.93°
                                                                                   2
                                                                                                 2
                                                                              2
                   Cari perimeter dan luas bahagian berlorek itu. DPelangi Sdn. Bhd.       2
                   Find the perimeter and area of the shaded region.        = 2.93 cm 2
                   4  = 5  + 5  – 2(5)(5) kos q  F  10 m    E
                        2
                            2
                    2
                          5  + 5  – 4 2
                           2
                               2
                    kos q =
                            2(5)(5)               B  4 m  C  8 m     3.  Rajah menunjukkan satu bulatan dengan pusat O
                       q   = 47.16°                                 Buku   dan jejari 7 cm. Diberi bahawa panjang lengkok
                                                                    Teks
                   ∠APB = ∠CPD                                      ms. 2-18  minor AB ialah 10 cm, cari
                          180° − 47.16°       A  5 m  P                 The diagram shows a circle with centre O and radius
                        =                                               7 cm. Given that the minor arc length AB is 10 cm, find
                                2
                        = 66.42° = 1.159 rad
                   Panjang lengkok AB = CD = 5(1.159)
                   Arc length           Penerbitan                                            O     B
                   Perimeter rantau berlorek
                   Perimeter of shaded region
                   = 2(8) + 10 + 4 + 2(5)(1.159)                                             A
                   = 41.59 cm                                           (a)  sudut q, dalam radian,
                                    66.42°                                  the angle q, in radian,
                                                2
                   Luas sektor APB =       × π(5) = 14.49 cm 2
                   Area of sector APB  360°                             (b)  luas sektor minor.
                               1                                            the area of the minor sector.
                   Luas ∆BCP  =  (5)(5)sin 47.16°
                               2
                             = 9.17 cm 2                                (a)   10 = 7(2π − q)
                   Luas rantau berlorek = 10 × 8 − 9.17 – 2(14.49)           7q = 14π − 10
                   Area of shaded region  = 41.85 m 2                        q = 4.85 rad
                                                                                   1     1
                                                                                             2
                                                                                     2
                2.  Rajah di bawah menunjukkan sebuah sektor            (b)  Luas =  j q =  (7) (2π − q)
                                                                                         2
                                                                                   2
               Buku   berpusat O.                                           Area   1    10
               Teks  The diagram below shows a sector with centre O.             =  (7) 2  
               ms. 2-18                                                            2     7
                                           P
                                                                                 = 35 cm 2
                                   15 cm

                                O           Q
                                                                18
         01 M&M Mate T Tg5.indd   18                                                                             09/12/2022   12:20 PM
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