Page 22 - PBD Plus Matematik T5 (EG)

Matematik Tingkatan 5 Bab 1 Ubahan
19. Selesaikan. TP 3
Solve.
Contoh
Diberi y = 0.25 apabila x = 8. Hitung nilai y apabila (a) Diberi p = 4 apabila q = 14. Hitung nilai p apabila
x = 0.02 jika q = 3.5 jika
Given that y = 0.25 when x = 8. Calculate the value y when Given that p = 4 when q = 14. Calculate the value p when
x = 0.02 if q = 3.5 if
1 1 (i) p ∝ 1 (ii) p ∝ 1
(i) y ∝ (ii) y ∝ q q 2
x x 2
k k k k
(i) y = (ii) y = (i) p = (ii) p =
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x x 2 q q 2
k k k k
0.25 = 0.25 = 4 = 4 =
8 8 2 14 14 2
k = 2 k = 16 k = 56 k = 784
2 16 56 784
y = y = p = p =
x x 2 q q 2
2 16 56 784
y = y = p = p =
0.02 (0.02) 2 3.5 (3.5) 2
y = 100 y = 40 000 p = 16 p = 64

20. Hitung nilai p dan nilai q bagi setiap yang berikut. TP 4
Calculate the value of p and of q for each of the following.
Contoh
y berubah secara songsang dengan x.
y varies inversely as x.
x 2 p 6
y 5 2.5 q

1 10 10
y ∝ y = y =
x x x
k 10 10
y = 2.5 = q =
x p 6
k 5
5 = p = 4 q =
2 3
k = 10

3
(a) y berubah secara songsang dengan √x . (b) y berubah secara songsang dengan x .
2
3
y varies inversely as √x . y varies inversely as x .
2
x 1 p 27 x 10 p 14
y 6 3 q 1
y 0.02 72 q

1 6
y ∝ 3 √x 3 = 3 √p y ∝ 1 1 = 2
k √p = 2 x 2 72 p 2
3
y = 3 k p = 144
2
√x p = 8 y = x 2
k p = ±12
6 = 3 √1 6 0.02 = k
k = 6 q = 3 √27 10 2 q = 2 2
6 q = 2 k = 2 14
y = 3 2 1
√x y = q =
x 2 98

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