Page 21 - PBD Plus Matematik T5 (EG)
P. 21

Matematik Tingkatan 5  Bab 1 Ubahan
            18.  Selesaikan.   TP 3
               Solve.
                  Contoh
                Diberi bahawa P = 5 apabila Q = 9. Ungkapkan P dalam sebutan Q jika
                Given that P = 5 when Q = 9. Express P in terms of Q if
                (i)  P berubah secara songsang dengan Q,
                   P varies inversely as Q,
                (ii)  P berubah secara songsang dengan punca kuasa dua Q.
                   P varies inversely as the square root of Q.
                        1                                                    1
                (i)  P ∝                                            (ii)  P ∝
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                        Q                                                   √Q
                        k                                                   k
                   P  =                                                P  =
                       Q                                                    √Q
                       k                                                    k
                   5 =                                                 5 =
                       9                                                   √9
                   k  = 45                                             k = 15
                       45                                                   15
                   P =                                                 P =
                        Q                                                   √Q

                (a)  Diberi bahawa m = 3 apabila n = 8. Ungkapkan m dalam sebutan n jika
                   Given that m = 3 when n = 8. Express m in terms of n if
                   (i)  m berubah secara songsang dengan n,
                       m varies inversely as n,
                   (ii)  m berubah secara songsang dengan punca kuasa tiga n.
                       m varies inversely as the cube root of n.


                            1                                             1
                    (i)  m ∝                                     (ii)  m ∝
                            n                                             3 √n
                            k                                             k
                       m  =                                         m  =
                            n                                            3 √n
                            k                                             k
                        3  =                                        3  =  3
                            8                                            √8
                        k  = 24                                     k  = 6
                            24                                            6
                       m =                                          m =
                            n                                            3 √n

                (b)  Diberi bahawa y = 5 apabila x = 2. Ungkapkan y dalam sebutan x jika
                   Given that y = 5 when x = 2. Express y in terms of x if
                   (i)  y berubah secara songsang dengan x ,
                                                         2
                                      2
                       y varies inversely as x ,
                   (ii)  y berubah secara songsang dengan 3x – 1.
                       y varies inversely as 3x – 1.
                            1                                              1
                    (i)   y  ∝                                   (ii)   y  ∝
                            x 2                                          3x – 1
                            k                                              k
                        y  =                                         y  =
                            x 2                                          3x – 1
                            k                                               k
                        5  =                                         5  =
                            2 2                                          3(2) – 1
                        k  = 20                                      5  =   k
                            20                                           5
                        y  =
                            x 2                                       k  = 25
                                                                          25
                                                                     y  =
                                                                         3x – 1




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