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Mathematics Term 2  STPM  Chapter 2 Differentiation
               Differentiation of standard functions

               Derivative of a constant
               Consider the function y = c, where c is a constant.              y
                                       dy         f(x + x) – f(x)
               From the derived definition    =   lim
                                       dx   x → 0     x
               As f(x + x) = c = f(x),                                        c                  y = c
               ∴   f(x + x) – f(x)    =   c – c
                         x           x
                                  = 0                                           0                    x
                      dy                                                                                    2
               Hence,      =   lim  0                                                 Figure 2.2
                      dx   x → 0
                         = 0

               Geometrically, y = c represents a straight line parallel to the x-axis.

               Therefore, its gradient is zero.
                d   (c) = 0, where c is a constant
               dx



               Derivative of af(x) where a is a constant
               From the derived definition,
                    d                a f(x + x) – a f(x)
                       [a f(x)] =   lim
                    dx         x → 0       x

                             =   lim    a[f(x + x) – f(x)] 4
                               x → 0       x
                             =   lim  a   lim  f(x + x) – f(x)] 4
                               x → 0  x → 0    x
                                 d
                             = a    [f(x)]
                                 dx

                        d            d
               Hence,      [a f(x)] = a    [f(x)]
                        dx           dx


               Derivative of x n

               Consider the following differentiation from first principles.
                          d           (x + x)  – x 2
                                             2
                             x   =   lim
                             2
                         dx     x → 0    x
                              =   lim  (2x + x)
                                x → 0
                              = 2x
                              = 2x 2 – 1




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       02 STPM Math(T) T2.indd   19                                                                 02/11/2018   12:43 PM
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