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WORK, ENERGY AND POWER                                                                     129

                Answer  The downward force on the elevator is    by the second particle. F is likewise the force
                                                                                         21
                                                                 exerted on the second particle by the first particle.
                  F = m g + F  = (1800 × 10) + 4000 = 22000 N
                             f                                   Now from Newton’s third law, F  = − F .  This
                The motor must supply enough power to balance    implies                        12     21
                this force.  Hence,
                                                                       ∆p + ∆p =  0
                P = F. v = 22000 × 2 = 44000 W = 59 hp         t         1     2
                                                                 The above conclusion is true even though the
                6.12  COLLISIONS                                 forces vary in a complex fashion during the
                In physics we study motion (change in position).  collision time ∆t. Since the third law is true at
                At the same time, we try to discover physical    every instant, the total impulse on the first object
                quantities, which do not change in a physical    is equal and opposite to that on the second.
                process. The laws of momentum and energy           On the other hand, the total kinetic energy of
                conservation are typical examples. In this       the system is not necessarily conserved. The
                section we shall apply these laws to a commonly  impact and deformation during collision may
                encountered phenomena, namely collisions.        generate heat and sound. Part of the initial kinetic
                Several games such as billiards, marbles or      energy is transformed into other forms of energy.
                carrom involve collisions.We shall study the     A useful way to visualise the deformation during
                collision of two masses in an idealised form.    collision is in terms of a ‘compressed spring’. If
                  Consider two masses m  and m .  The particle   the ‘spring’ connecting the two masses regains
                                        1       2                its original shape without loss in energy,  then
                m  is moving with speed v , the subscript ‘i’
                 1                        1i                     the initial kinetic energy is equal to the final
                implying initial. We can cosider m   to be at rest.
                                                2                kinetic energy but the kinetic energy during the
                No loss of generality is involved in making such
                a selection. In this situation the  mass m       collision time ∆t is not constant. Such a collision
                                                            1    is called an elastic collision. On the other hand
                collides  with  the stationary  mass m   and  this
                                                   2             the deformation may not be relieved and the two
                is depicted in  Fig. 6.10.
                                                                 bodies could move together after the collision. A
                                                                 collision in which the two particles move together
                                                                 after the collision is called a completely inelastic
                                                                 collision. The intermediate case where the
                                                                 deformation is partly relieved and some of the
                                                                 initial kinetic energy is lost is more common and
                                                                 is appropriately called an inelastic collision.
                                                                 6.12.2  Collisions in One Dimension
                                                                 Consider first a completely inelastic collision
                Fig. 6.10 Collision of mass m , with a stationary mass m .
                                       1                    2    in one dimension. Then,  in Fig. 6.10,
                The masses m     and m    fly-off in different
                               1        2                           θ   = θ   = 0
                directions.   We shall see that there are            1    2
                relationships, which connect the masses, the        m v  = (m +m )v   (momentum conservation)
                                                                             1
                                                                                 2
                                                                                   f
                                                                      1 1i
                velocities and the angles.                                 m
                                                                    v =      1   v
                6.12.1  Elastic and  Inelastic Collisions             f  m +  m   1i                                (6.23)
                                                                           1    2
                In all collisions the total linear momentum is   The loss in kinetic energy on collision is
                conserved; the initial momentum of the system
                is equal to the final momentum of the system.       ∆ K =  1   2  −  1  m +   2
                                                                                            )
                One can argue this as follows.  When two objects         2  m v   2  (  1  m v  f
                                                                                           2
                                                                             1 1i
                collide, the mutual impulsive forces acting over
                the collision time ∆t  cause a change in their       1    2  1    m  2   2
                respective momenta :                                   =  m v −     1   v     [using Eq. (6.23)]
                                                                                         1i
                                                                        1 1i
                                                                     2       2  m +  m  2
                                                                                  1
                     ∆p = F    ∆t
                        1   12
                     ∆p = F    ∆t                                        1           m    
                        2   21                                         =  m v 2   1  −  1  
                where F  is  the force exerted on the first particle     2  1 1i    m 1  + m 2 
                       12

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