Page 154 - Engineering Mathematics Workbook_Final
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Complex Variables


                           ( )
            126.  Let  f z =       e z    be  a  complex                 (d) The function f has zeros of order
                                                                         2 at 2 n , n =  
                                  z 2018                                                  1, 2,...
                   function. Then
                                                                                       [NET JUNE 2013]
                   (a) f(z) has a simple pole at z = 0
                                                                  129.  Consider the function
                   (b) f(z) has a pole at  z = 0 of order
                                                                                      ( z
                   2018                                                           sin    /  ) 2
                                                                          f  ( ) z =          .  Then  f  has
                                                                                       ( ) z
                   (c)  The  residue  of  f(z)  at  z  =  0  is                    sin 
                      1                                                  poles at
                    2017!                                                (a) all integers

                                                                         (b) all even integers
                   (d)  The  residue  of  f(z)  at  z  =  0  is
                      1                                                  (c) all odd integers

                    2018!                                                (d)  all  integers  of  the  form  4k + 1,

                                                                              Z
            127.  The  value  of  the  contour  integral                 k 
                        2
                                                                                     →
                        z − 1 dz  is                            130.  Let  f   :C C   be  a  holomorphic
                         z                                               function and let u be the real part of f
                   (a)  0,  when  the  curve  is  a                     and     be  the  imaginary  of  f.  Then,
                   semicircle  z =  2e i (0       )                 for  , x y  ,  f  ( ' x   ) y  2   is  equal
                                                                                               +
                                                                                    R
                   (b)  − i ,  when  the  curve    is  a               to
                                                   )
                                            
                   semicircle  z =  2e i (                           (a) u +  u            (b) u +  u
                                                                                    2
                                                                              2
                                                                                                         2
                                                                                                    2
                                                                              x
                                                                                                    x
                                                                                    y
                                                                                                         y
                   (c)  − i ,  when  the  curve    is  a               (c) u +  u            (d) u −  u
                                                                                                    2
                                                                              2
                                                                                    2
                                                                                                         2
                   semicircle  z =  2e i (    2 )                        y     y               x    y
                                           
                                                                  131.  Let f(z) be the meromorphic function
                        −
                   (d)  2i ,  when  the  curve    is  a                                         z
                                                                                   f
                   semicircle  z =  2e i (0     2   )               given by  ( ) z =               . Then
                                                                                              −
                                                                                            (1 e  z )sin z
            128.  Consider the function
                                         )
                                              
                                 −
                    f  ( ) z =  z 2 (1 cos z ,  z C . Which              (a) z = 0 is a pole of order 2.
                                                                                                       
                                                                                             Z
                   of the following are correct?                         (b)  For  every  k  ,  z =  2 ik   is  a
                                                                         simple pole.
                   (a) The function f has zeros of order 2
                                                                                                       =
                                                                                                          k
                   at 0                                                  (c) For every  k    / z    0 ,  z   is a
                   (b) The function f has zeros of order                 simple pole.
                                      
                         
                   1 at 2 n , n =  1, 2,.....                           (d)  z  =  2 i  is a pole.
                                                                                        +
                   (c) The function f has zeros of order 4
                   at 0.

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