Page 93 - Engineering Mathematics Workbook_Final
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Differential Equations & Partial Differential Equations

                                        1                                    1
                                           x
                   (a) c e − 2x  +  c e −  3x  e                         (c)  e x /2  +  2cos4x +  5sin4x
                        1
                                 2
                                        4                                    5
                                       1                                 (d) 2cos4x +   5sin4x
                                          x
                   (b) c e +  2x  c e +  3x  e
                        1
                                2
                                       4
                                                                                               [JAM GP 2005]
                                        1
                                           x
                   (c) c e +  2x  c e − 3x  −  e                  52.    Consider the differential equation
                        1
                                2
                                        4
                                                                          y +  6y +   25y =  with initial
                                                                                  1
                                                                           11
                                                                                             0
                                        1
                                           x
                   (d) c e − 2x  +  c e +  3x  e                         condition  ( ) 0 = . Then, the
                                                                                    y
                                                                                            0
                        1        2
                                        4
                                                                         general solution of the initial value
                                        [JAM MA 2008]                    problem is
                                 y
            50.    The solution  ( ) x  of the differential                   − 3x
                                                                                            +
                                                                         (a) e   ( cos4A  x B   sin4x  )
                               2
                             d y      dy
                                                  0
                   equation       +  4    +  4y =                               − 3x
                             dx 2     dx                                 (b)  Be   sin4x
                                                      4
                                              y
                   satisfying the conditions  ( ) 0 = ,                         − 4x
                                                                         (c)  Ae   sin3x
                    dy  ( ) 0 =  is
                             8
                                                                                            +
                                                                                   A
                    dx                                                   (d) e − 4x  ( cos3x B  sin3x  )
                          2x
                   (a) 4e                                                                      [JAM GP 2006]
                   (b) (16x +   ) 4 e − 2x                        53.    The differential equation
                                                                           2
                                                                          d y  +  y =  0 satisfying  ( ) 0y  = 1,
                   (c) 4e − 2x  + 16x                                     dx 2
                                                                          y  =
                                                                           ( ) 0 has
                                     2x
                   (d) 4e − 2x  + 16xe
                                                                         (a) a unique solution
                                        [JAM MA 2011]
                                                                         (b) a singly infinite family of
            51.    The particular integral of the
                   following differential equation                       solutions
                                                                         (c) no solution
                    y +  11  2y +  1  5y
                                                                         (d) a doubly infinite family of
                      5
                   =   e x / 2 x + 18cos4x − 71sin 4x is                 solutions
                      4                                                                        [JAM GP 2008]
                                                                  54.    The particular integral of the
                       5
                   (a)  e x /2  +  5cos4x                                differential equation
                       4
                                                                          y +  y +  3y =  5cos (2x +   ) 3  is
                                                                           11
                                                                                 1
                   (b) 5cos4x +   2sin4x





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