Page 98 - Engineering Mathematics Workbook_Final
P. 98

Differential Equations & Partial Differential Equations

            78.    If  y =  f  ( ) t  satisfies the boundary             (a)
                                                                                                             
                                                                                    +
                                                                                                 +
                                                                                                              
                   value problem  y +  11  9y =  0,                          c +  c x c 3 sin 3x c 4 cos 3x
                                                                                                              
                                                                                 2
                                                                            1
                                                                                               
                                                  )
                    y      )    2 , then  ( / 4  is                     and  3x −       4  12x +  2  c
                     ( / 2 =
                                          y 
                                                                                               
                                                                                               
                   _______________.
                                                                                                              
                                         [GATE-2016]                     (b)  c X +        2  c 3 sin 3x +  c 4 cos 3x
                                                                                                              
                                                                                                              
                                                                                               
            79.    The particular solution of the initial                and  5x −       4  12x +  2  c
                                                                                               
                                                                                               
                   value problem given below is
                                                                                                            
                                                                                              +
                                                                                                            
                     2
                    d y       dy                                         (c)  c +        1  c 3 sin 3x c 4 cos 3x
                                                                                                            
                                          0
                         + 12    + 36y =  with
                                                                                               
                    dx 2      dx                                         and  3x −     4  12x +  2  c
                                                                                               
                                   dy                                                         
                    y ( ) 0 =  3 and      = −  36
                                   dx  x= 0                              (d)
                                                                           c +  c x c  sin 3x c              
                                                                                    +
                                                                                                 +
                                                                                                              
                                )
                                                                                                              
                          −
                   (a) (3 18x e   − 6x                                       1  2    3            4 cos 3x
                                                                                               
                                                                         and  5x −       4  12x +  2  c
                                                                                               
                                                                                               
                                )
                          +
                   (b) (3 25x e    − 6x
                                )
                          +
                   (c) (3 20x e    − 6x                                              [GATE-2016-CE-SET-1]
                                                                  82.    What is the solution for the second
                                )
                          −
                   (d) (3 12x e    − 6x   [GATE-2016]                    order differential equation
                                                                           2
                                                                          d y
            80.    Let y(x) be the solution of the                        dx 2  +  y =  0, with the initial
                   differential equation                                                           dy
                     2
                    d y  − 4 dy  + =                                     conditions  y  x= 0  = 5 and   dx  = 10 ?
                                  4 0 with initial
                    dx 2     dx                                                                        x= 0
                                                                                   +
                                              dy                         (a)  y =  5 0sin x
                                       0
                               y
                   conditions  ( ) 0 =  and          = 1.
                                              dx  x= 0
                                                                                       −
                   Then the value of y(1) is _______.                    (b)  y =  5cos 5sin x
                               [GATE-2016-EE-SET-2]                      (c)  y =  5cosx +  10x
            81.    The respective expressions for                        (d)  y =  5cosx +  10sin x
                   complimentary function and
                   particular integral part of the solution                                [GATE-2016 (CH)]
                   of the differential equation
                              2
                     4
                    d y  +  3 d y  =  108x  are                   83.    The general solution of the
                                         2
                    dx 4     dx 2                                        differential equation
                                                                           2
                                                                          d y  +  2  dy  − 5y =  in terms of
                                                                                              0
                                                                          dx 2     dx
                                                                         arbitrary constant  K  and  K  is
                                                                                              1
                                                                                                       2

                                                             96
   93   94   95   96   97   98   99   100   101   102   103