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Solution (a)
We must find scalars , , such that
or, in terms of components,
Equating corresponding components gives
Solving this system, we obtain , , (verify). Therefore,
Solution (b) , we obtain
Using the definition of the coordinate vector
EXAMPLE 5 Standard Basis for
(a) Show that is a basis for the vector space of polynomials of the form .
for .
(b) Find the coordinate vector of the polynomial relative to the basis
Solution (a)
We showed that S spans in Example 11 of Section 5.2, and we showed that S is a linearly independent set in Example 5 of
Section 5.3. Thus S is a basis for ; it is called the standard basis for .
Solution (b)
The coordinates of are the scalar coefficients of the basis vectors 1, x, and , so .
EXAMPLE 6 Standard Basis for
Let

