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378                                CHAPTER 12  Rotation of a Rigid Body



                                                      Evaluating this expression at t   3.0 s, we find
                                                                                       2        3
                                                                                  (3.0s)   (3.0 s)
                                                                             2
                                                          f   f   60 radians>s   a               b   180 radians
                                                               0
                                                                                    2       18 s
                                                      Hence the number of revolutions during the acceleration is
                                                                              f   f 0  180  radians
                                                        [number of revolutions]                    29 revolutions  (12.25)
                                                                                2p         2p


                                                      As discussed in Section 2.7, similar integration techniques can be applied to deter-
                                                   mine any component of the translational velocity and the position when the time-
                                                   dependent net force and, thus, the time-dependent translational acceleration are known.
                                                   In Section 2.7 we also examined the case when the acceleration is a known function
                                                   of the velocity; in that case, integration provides t as a function of v (and v ), which can
                                                                                                            0
                                                   sometimes be inverted to find v as a function of t.
                                                      We saw in Chapters 7–9 that a conservation-of-energy approach is often the eas-
                                                   iest way to determine the motion when the forces are known as a function of position.
                                                   Now we have seen that direct integration of the equations of motion can be applied when
                                                   the translational or angular acceleration is known as a function of time or of velocity.


                                                    ✔      Checkup 12.4



                                                   QUESTION 1: Beginning from rest at t   0, the angular velocity of a merry-go-round
                                                   increases in proportion to the square root of the time t. By what factor is the angular
                                                   position of the merry-go-round at t   4 s greater than it was at t   1 s?
                                                   QUESTION 2: A car on a circular roadway accelerates from rest beginning at t   0, so
                                                   that its angular acceleration increases in proportion to the time t. With what power of
                                                   time does its centripetal acceleration increase?
                                                                     2            3           4            5
                                                      (A) t      (B) t        (C) t       (D) t        (E) t




                                                   12.5 KINETIC ENERGY OF ROTATION;
                                                   MOMENT OF INERTIA


                                                   A rigid body is a system of particles, and as for any system of particles, the total kinetic
                                                   energy of a rotating rigid body is simply the sum of the individual kinetic energies of
                                                   all the particles (see Section 10.4). If the particles in the rigid body have masses m , m ,
                                                                                                                  1  2
                                                   m ,... and speeds v ,v ,v ,..., then the kinetic energy is
                                                    3              1  2  3
                                                                                     2
                                                                                             2
                                                                              2
                                                                         1
                                                                                         1
                                                                                 1
                                                                     K   m v  	 m v  	 m v  	                   (12.26)
                                                                                   2 2
                                                                                 2
                                                                                           3 3
                                                                                         2
                                                                         2
                                                                            1 1
                                                   In a rigid body rotating about a given axis, all the particles move with the same angu-
                                                   lar velocity   along circular paths. By Eq. (12.11), the speeds of the particles along
                                                   their paths are proportional to their radial distances:
                                                                 v   R  ,   v   R  ,   v   R  ,                 (12.27)
                                                                  1
                                                                                            3
                                                                                        3
                                                                       1
                                                                             2
                                                                                  2
                                                   and hence the total kinetic energy is
                                                                      1
                                                                                          1
                                                                                1
                                                                          2 2
                                                                                    2
                                                                                       2
                                                                                               2 2
                                                                  K   m R   	 m R   	 m R
                                                                                               3
                                                                                            3
                                                                                2
                                                                      2
                                                                        1 1
                                                                                          2
                                                                                    2
                                                                                  2
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