Page 12 - TOP ONE ADDMATHS TG4
P. 12

Additional Mathematics  Form 4  Chapter 2 Quadratic Functions

                15.  Express each of the following quadratic functions in the form of f(x) = a(x – h)  + k. Then, state the minimum
                                                                                         2
                    or maximum value, axis of symmetry and minimum or maximum point.  PL 3
                                                                         2
                    Ungkapkan setiap fungsi kuadratik berikut dalam bentuk f(x) = a(x – h)  + k. Kemudian, nyatakan nilai minimum atau maksimum,
                    paksi simetri dan titik minimum atau maksimum.
                                                                              Minimum /                 Minimum /
                                                                              maximum        Axis of     maximum
                      Quadratic function           f(x) = a(x – h)  + k          value      symmetry       point
                                                                2
                         Fungsi kuadratik
                                                                             Nilai minimum /  Paksi simetri  Titik minimum /
                                                                               maksimum                   maksimum
                      Example
                                                  2
                    f(x) = x  – 2x + 5     f(x) = x  – 2x + 5                Minimum                   Minimum
                           2
                                                                 
                                                      
                                           = x  – 2x +  –   2  2  + 5 –  –   2  2  value             point
                                              2
                                                                                                       = (1, 4)
                     a . 0, shape                       2           2        = 4              x = 1
                                              2
                                                         2
                     which passes          = x  – 2x + (–1)  + 5 – (–1) 2
                     through minimum       = (x – 1)  + 5 – 1
                                                   2
                     point                                    Add and subtract
                                           = (x – 1)  + 4                 2
                                                   2
                                                               coefficient of x 
                                                                   2
                    (a)  f(x) = x  – 6x – 3  f(x) = x  – 6x – 3              Minimum          x = 3    Minimum
                               2
                                                  2
                                                                 
                                                      
                                              2
                                           = x  – 6x +  –   6  2  – 3 –  –   6  2  value             point
                                                                    2
                                                        2
                                                                             = –12
                                                                                                       = (3, −12)
                                           = x  – 6x + (–3)  – 3 – (–3) 2
                                              2
                                                         2
                                                   2
                                           = (x – 3)  – 3 – 9
                                                   2
                                           = (x – 3)  – 12
                                                   2
                                2
                    (b)  f(x) = –x  + 2x – 8  f(x) = –x  + 2x – 8            Maximum          x = 1    Maximum
                                           = –[x  – 2x + 8]                  value                     point
                                                2
                                              
                                                                        2
                                                                      2
                                                        
                                                                   
                                                                       
                                           = – x  – 2x +  –   2  2  + 8 –  –  2   = –7               = (1, −7)
                                                2
                                                          2
                                                                      2
                                           = –[x  – 2x + (–1)  + 8 – (–1) ]
                                                           2
                                                2
                                           = –[(x – 1)  + 8 – 1]
                                                     2
                                                     2
                                           = –[(x – 1)  + 7]
                                           = –(x – 1)  – 7
                                                    2
                                                   2
                                2
                    (c)  f(x) = 2x  + 10x + 7 f(x) = 2x  + 10x + 7           Minimum         x = –   5  Minimum
                                              
                                                        7
                                           = 2 x  + 5x +  2                 value 11              2   point 5  11 
                                                2
                                                                                                         
                                                                             = –
                                                                                                       =  –  , –
                                                                   2 
                                              
                                                                   5
                                                         5
                                                               7
                                           = 2 x  + 5x +    2  +   –    2     2                         2    2
                                                2
                                                         2
                                                               2
                                              
                                                              4 
                                                         7
                                               
                                           = 2 x +   5  2  +   –   25
                                                    2
                                                         2
                                              
                                                          4 
                                               
                                           = 2 x +   5  2  –   11
                                                    2
                                              
                                           = 2 x +   5  2  –   11
                                                   2
                                                         2
                                                                 27                              © Penerbitan Pelangi Sdn. Bhd.
       02 TOP 1 + MATH F4.indd   27                                                                             20/12/2019   9:34 AM
   7   8   9   10   11   12   13   14   15   16   17