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Additional Mathematics  Form 4  Chapter 2 Quadratic Functions

                17.  Sketch the graph of each of the following quadratic functions.  PL 4
                    Lakarkan graf bagi setiap fungsi kuadratik berikut.

                      Example
                                                                                         2
                    f(x) = x  – x – 6 for / untuk –3 < x < 4         When x = 0, f(0) = (0)  – 0 – 6
                           2
                                                                                     = –6
                    a . 0, then the shape of the graph is   .
                                                                     ∴ The y-intercept is (0, –6).
                                              2
                                  2
                    Discriminant, b  – 4ac = (–1)  – 4(1)(–6)
                                                                                             2
                                        = 1 + 24                     When  x = –3, f(–3) = (–3)  – (–3) – 6
                                        = 25 . 0                                           = 9 + 3 – 6
                             2
                    ∴ f(x) = x  – x – 6 has two different real roots.                  = 6
                                                                     ∴ (−3, 6)                    Range: –3 < x < 4
                    f(x) = x  – x – 6                                When x = 4, f(4) = (4)  – 4 – 6
                                                                                         2
                           2
                                 
                                            
                           2
                        = x  – x +  –   1  2  – 6 –  –   1  2                      = 16 – 4 – 6
                                               2
                                    2
                                                                                     = 6
                          
                        = x –   1  2  – 6 –   1                     ∴ (4, 6)            f(x)
                              2
                                       4
                          
                        = x –   1  2  –   25                                   (–3, 6)    x =  1 2  (4, 6)
                                2   4
                    ∴ The minimum point is    1  , –6  1  .
                                            2
                                                  4
                                              1
                    The axis of symmetry is x =  .
                                              2                                      –2  0     3          x
                    When  f(x) = 0, x  – x – 6 = 0                                                2
                                    2
                               (x – 3)(x + 2) = 0                                             f(x) = x  – x – 6
                                            = 3  or  x = –2
                                                                                       –6    1  1
                                                                                            (    , –6   )
                    ∴ The x-intercepts are (3, 0) and (–2, 0).                               2  4
                    (a)  f(x) = x  – 4x – 5 for / untuk –2 < x < 6
                               2
                         a . 0, then the shape of the graph is   .     When x = 0, f(0) = (0)  – 4(0) – 5
                                                                                           2
                                                                                       = –5
                                      2
                                                  2
                         Discriminant, b  – 4ac = (–4)  – 4(1)(–5)
                                             = 16 + 20                 ∴ The y-intercept is (0, –5).
                                             = 36 . 0
                                                                       When  x = –2, f(–2) = (–2)  – 4(–2) – 5
                                                                                               2
                                  2
                         ∴ f(x) = x  – 4x – 5 has two different real roots.              = 4 + 8 – 5
                                                                                         = 7
                                                                       ∴ (–2, 7)
                               2
                         f(x) = x  – 4x – 5
                                       
                                                  
                                                                                           2
                            = x  – 4x +  –   4  2  – 5 –  –   4  2    When x = 6, f(6) = (6)  – 4(6) – 5
                               2
                                                    2
                                         2
                                                                                       = 36 – 24 – 5

                               2
                                          2
                            = x  – 4x + (–2)  – 5 – (–2) 2                             = 7
                                    2
                            = (x – 2)  – 5 – 4                         ∴ (6, 7)
                                    2
                            = (x – 2)  – 9
                                                                                       f(x)
                         ∴ The minimum point is (2, –9).                       (–2, 7)      x = 2  (6, 7)
                           The axis of symmetry is x = 2.
                                                                                                          x
                                                                                    –1  0        5
                                        2
                         When f(x) = 0, x  – 4x – 5 = 0
                                    (x – 5)(x + 1) = 0                               –5         f(x) = x  – 4x – 5
                                                                                                    2
                                               x = 5  or  x = –1

                         ∴ The x-intercepts are (5, 0) and (–1, 0).                         (2, –9)
                                                                 29                              © Penerbitan Pelangi Sdn. Bhd.
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