Page 31 - Matematik Tingkata 3

Bab 1 IndeksIndeks
Bab 1

Contoh 16

1. Hitung nilai setiap yang berikut. 1
4
1
3
3
—
– —
—
—
1
1
2 2
2 × 125
49 — – — 16 × 81 (243 × 5 )
4
5
4
3
(a) ———————– (b) —————– (c) —————– BAB
1
4 √2 401 × √3 125 (2 × 3 4 — 4 √81 × √25 4
5
2 )
6
Penyelesaian:
3
1
—
– —
—
3
—
4
1
2 2
1
49 — – — 16 × 81 (243 × 5 )
2 × 125
4
4
5
3
(a) ——————— (b) —————– (c) —————
1
4 √2 401 × √3 125 (2 × 3 4 — 4 √81 × √25 4
6
5
2 )
1
1
3(– —)
1
3
—
4
3
–
7
2(—)
× 5
4 —
2
= ——————– 2 4 ( ) × 3 ( ) 243 — (2) × 5 — (2)
3
2
5
4
4
= ————––––––
= —————––
1
5 —
(7 ) × (5 ) 5 1 2 6 3 ( ) 4 — 81 × 25 —
4 —
( )
2
1
1
1 —
4
—
2 × 3
4
4
2
2
1
7 × 5 –1 2 × 3 5 — ( )

–1
3
8
= ———– = ———– 3 5 × 5 3
7 × 5 1 2 × 3 2 = ————––
1
3
2 — ( )
4 — ( )
1
4

= 7 1–1 × 5 –1 –1 = 2 3 – 3 × 3 –1 – 2 3 4 × 5 2
8
0
= 7 × 5 –2 0 –3 3 × 5 3
= ———
1
1
= 1 × — = 2 × 3 3 × 5 4
1
5 2 = 1 × — = 3 8 – 1 × 5 3 – 4
3
3
1
= — 1 = 3 × 5 –1
7
25 = —
27
3 7
= —
5
2 187
= ——–
5
2
= 437 —
5
UJI MINDA 1.2j
1. Permudahkan setiap yang berikut.
1
3 2 3 — 2 — 2 (mn ) × (√mn) 4 √25x yz × 4x z
2 3
2
2
3
√c d e × c d e 3
3
(a) ———————– (b) ——————– (c) ——————–
–3 2
2
2
5
6 3 —
(c d e) (m n ) 3 √36x yz 8

2. Hitung nilai setiap yang berikut. 1 3
—
2 —
6

4
– 4

√7
× 11
6
4
–3

(5 × 3 ) × √16
3
(2 × 3 × 5 ) 2
(a) ———— 4 (b) ———————–– (c) —————————
1
3

49 × 121 ( 125 × 729 × 64) – — 4 √256 × √729 × √125
3
1
1
—
2
6
3
9
√512 × √343 × √121
— –3
(d) ————————–––––– (e) ———————–—– (f) —————————–
4
3 × √125 × (2 × )
3
— 3
64
(2 × 3 ) × √8 × √81
2
5
1
3
4 × 27
1
3
1
4 × √625
(64) — — — 16 — — 2 4
3 × (81) × (14 641)
3
4
4
n
1
m
—
3. Diberi bahawa m = 2 dan n = –3. Hitung nilai bagi 64 × 512 (– —) ÷ 81 — .
n
3
2m
2
1
a

b
4. Diberi bahawa a = — dan b = —. Hitung nilai bagi 144 ÷ 64 × 256 — . Saiz sebenaraiz sebenar
a
S
b
2 3
21
21