Page 126 - C:\Users\trainee\AppData\Local\Temp\msoEAA3.tmp
P. 126

Fundamentals of Stress and Vibration                1. Mathematics for Structural mechanics
                 [A Practical guide for aspiring Designers / Analysts]














                      [Fig 1.28: Parallelogram law of Vectors]


                From [Fig 1.28], the longer diagonal of the parallelogram is given by:


                                            2
                                2
                                                          2
                                                                                    2





                    a    +  b cosθ  +   b sinθ  =   a    +  b  cos θ + 2 a    b cosθ +  b  sin θ

                                                    2
                                                                                        2
                                                               2
                Applying the fact that sin θ + cos θ = 1) in the above equation, we get:
                                                2
                                       2
                          2


                   a    +  b  + 2 a    b cosθ   - - - - (1.26)
                    2
                From the above discussion, we have the magnitudes of vectors [ a   ] and [ b ] to be:

                  a    =  a + a     and     b  =  b + b

                                               2
                              2
                                                    2
                         2
                                               x
                              y
                         x
                                                    y
                Substituting the magnitudes of the vectors in equation (1.26), we get:
                 a + a + b + b + 2 a + a  b + b  cosθ          - - - - (1.27)
                                 2
                   2
                                         2
                                                      2
                            2
                       2
                                                  2
                                              2
                                                  x
                                                      y
                                         x
                                              y
                       y
                                 y
                   x
                            x
                Equating, expression (1.27) with (1.25), we have:
                      2
                           2
                                                      2
                                                                    2
                a + b + a + b + 2 a b + a b   = a + a + b + b + 2 a + a  b + b  cosθ
                                                               2
                 2
                                                           2
                               2
                                                                                     2
                                                                                 2
                                                                            2
                                                                                          2
                                                                    y
                                                           y
                                                               x
                                                                                         y
                                                                                 y
                                                                                     x
                                                                            x
                                      x x
                 x
                                             y y
                               y
                           y
                      x
                                                      x
                Cancelling the common terms in the above expression, we have:
                           a b + a b
                  cosθ =    x x    y y
                         a + a   b + b   2
                                    2
                               2
                           2
                           x   y    x    y
                The denominator   a + a   b + b  , is the product of magnitude of two vectors.
                                              2
                                     2
                                         2
                                                   2
                                         y
                                                   y
                                     x
                                              x
                              QP No. SSC/Q4401, Version 1.0, NSQF Level 7, Compliant with Aero and Auto Industries,   Page 29
   121   122   123   124   125   126   127   128   129   130   131