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                            Hydrogen-1  Hydrogen-2  Hydrogen-3            the same, and the sum of the subscripts (atomic  number, or
                                                                          numbers of protons) in the reactants must equal the sum of the
                                1p         1p          1p                 subscripts in the products; and (2) the total number of nucleons
                                0n         1n          2n                 remains the same, and the sum of the superscripts (atomic mass,
                                                                          or number of protons plus neutrons) in the reactants must equal
                                                       3
                               1 1 H       1 H         1 H                the sum of the superscripts in the products. The new nucleus
                                           2
                                                                          remaining after the emission of an alpha particle, therefore, has
                                        (deuterium)  (tritium)            an atomic number of 90 (92 – 2 = 90). According to the table
                                                                          of atomic numbers on the inside back cover of this text, this
                                                                          new nucleus is thorium (Th). The mass of the thorium isotope
                                       Mass                               is 238 minus 4, or 234. The emission of an alpha particle thus
                                       number                             decreases the number of protons by 2 and the mass number
                                             H                            by 4. From the subscripts, you can see that the total charge is
                                       Atomic
                                       number                             conserved (92 = 90 + 2). From the superscripts, you can see
                                                                          that the total number of nucleons is also conserved (238  =
                   FIGURE 13.4  The three isotopes of hydrogen have the same   234  +  4). The mass numbers (superscripts) and the atomic
                   number of protons but different numbers of neutrons. Hydrogen-1   numbers (subscripts) are balanced in a correctly written nuclear
                   is the most common isotope. Hydrogen-2, with an additional neu-  equation. Such nuclear equations are considered to be indepen-
                   tron, is named deuterium, and hydrogen-3 is called tritium.
                                                                          dent of any chemical form or chemical reaction. Nuclear reac-
                                                                          tions are independent and separate from chemical reactions,
                   Subatomic particles involved in nuclear reactions are repre-  whether or not the atom is in the pure element or in a com-
                   sented by symbols with the following form:             pound. Each particle that is involved in nuclear reactions has
                                                                          its own symbol with a superscript indicating mass number and
                                                                          a subscript indicating the charge. These symbols, names, and
                                                                          numbers are given in Table 13.1.


                                                                          EXAMPLE 13.1
                                                                          A plutonium-242 nucleus undergoes radioactive decay, emitting
                   Symbols for these particles are illustrated in Table 13.1.
                                                                          an alpha particle. Write the nuclear equation for this nuclear reaction.
                      Symbols are used in an equation for a nuclear reaction
                   that is written much as a chemical reaction with reactants and
                   products. When a uranium-238 nucleus emits an alpha particle   SOLUTION
                    4
                   (      He), for example, it loses two protons and two neutrons. The   Step 1:  The table of atomic weights on the inside back cover gives

                    2
                   nuclear reaction is written in equation form as
                                                                                 the atomic number of plutonium as 94. Plutonium-242
                                                                                                    242
                                    238   234    4                               therefore has a symbol of         Pu. The symbol for an alpha
                                             U →          Th +         He                4              94
                                            90
                                                 2
                                      92

                                                                                 particle is   (       He), so the nuclear equation so far is
                                                                                         2
                   The  products of this nuclear reaction from the decay of a                242    4
                                                          4                                           Pu →         He + ?
                                                                                               94
                                                                                                    2
                   uranium-238 nucleus are (1) the alpha particle (      He) given off


                                                          2
                   and (2) the nucleus, which remains after the alpha particle leaves   Step 2:  From the subscripts, you can see that 94 = 2 + 92, so the
                   the original nucleus. What remains is easily determined since all   new nucleus has an atomic number of 92. The table of
                   nuclear equations must show conservation of charge and con-   atomic weights identifies element 92 as uranium with a
                   servation of the total number of nucleons. In an alpha emission   symbol of U.
                   reaction, (1) the number of protons (positive charge) remains   Step 3:  From the superscripts, you can see that the mass number of
                                                                                 the uranium isotope formed is 242 – 4 = 238, so the prod-
                                                                                           238
                                                                                 uct nucleus is          U and the complete nuclear equation is
                                                                                             92
                    TABLE 13.1                                                              242   4    238
                                                                                                     Pu →          He +          U
                                                                                                  2
                                                                                                         92
                                                                                              94
                    Names, symbols, and properties of subatomic particles in
                                                                          Step 4:  Checking the subscripts (94 = 2 + 92) and the superscripts
                    nuclear equations
                                                                                 (242 = 4 + 238), you can see that the nuclear  equation is
                    Name           Symbol       Mass Number   Charge             balanced.
                                   1    1


                    Proton               H (or        p)  1     1+
                                   1
                                        1
                                     0    0
                    Electron               e (or          β)  0  1–       EXAMPLE 13.2
                                        –1
                                   –1
                                   1

                    Neutron              n          1           0         What is the product nucleus formed when radium emits an alpha par-
                                   0
                                   0

                    Gamma photon           γ        0           0         ticle? (Answer: Radon-222, a chemically inert, radioactive gas)
                                   0
                   326     CHAPTER 13 Nuclear Reactions                                                                  13-4
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