Page 17 - PBD Plus Matematik T5 (EG)

Matematik Tingkatan 5 Bab 1 Ubahan
SP 1.1.4 Menyelesaikan masalah yang melibatkan ubahan langsung.

14. Selesaikan. TP 5
Solve.
(a) Fahmee meneliti bil air bulanan yang baru diterimanya. Kadar penggunaan air, V m , adalah berkadaran
3
secara langsung dengan caj bil bulanan, RMQ. Bagi bulan tersebut, kadar penggunaan air ialah 7 m
3
dan dikenakan bayaran sebanyak RM3.10.
Fahmee viewed the monthly water bill he had just received. The rate of water usage, V m , is directly proportional to the monthly bill
3
charge, RMQ. For that month, the rate of water usage is 7 m and is charged at RM3.10.
3
(i) Tulis satu persamaan yang menghubungkan V dan Q.
Write an equation that relates V and Q.
(ii) Pada suatu bulan dalam musim PKP, caj bil bulanan bagi penggunaan air melonjak sehingga
RM20.09. Berapakah kadar penggunaan air pada bulan tersebut?
On a certain month during MCO, the monthly bill charge for water has increased to RM20.09. What is the rate of water usage
on that month?
(i) V ∝ Q (ii) V = 70 Q
V = kQ 31
7 = k(3.10) V = 70 (20.09)
70 31
k =
31 V = 45.36 m
3
70
V = Q
31
(b) Musaimah mendapati berat adunan roti, x g, berubah secara langsung dengan bilangan biji roti yang
terhasil, t. Satu adunan roti seberat 1 950 g boleh menghasilkan 48 biji roti.
Musaimah noticed that weight of a bread dough, x g, varies directly as the number of buns produced, t. One dough of bread weighted
1 950 g can produce 48 buns.
(i) Tulis satu persamaan yang menghubungkan x dan t.
Write an equation that relates x and t.
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(ii) Musaimah menerima tempahan sebanyak 200 biji roti. Berapakah berat adunan yang perlu
disediakan untuk tempahan tersebut?
Musaimah has received an order of 200 buns. How much is the weight of the dough that she needs to prepare for the order?
(i) x ∝ t (ii) x = 325 t
x = kt 8
1 950 = k(48) x = 325 (200)
325 8
k =
8 x = 8 125 g
325
x = t
8

(c) Kadar penggunaan elektrik, V kWh adalah berkadaran secara langsung dengan caj bil bulanan,
RMR. Bil elektrik rumah Maher bagi suatu bulan tertentu ialah RM75 dan kadar penggunaan elektrik
bulan tersebut ialah 294 kWh. Sekiranya Maher ingin mengawal perbelanjaan tidak tetapnya kepada
maksimum RM50 sahaja sebulan untuk bil elektrik, berapakah kadar penggunaan elektrik bulanan
maksimum?
The rate of electricity consumption, V kWh is directly proportional to the monthly bill charge, RMR. The electricity bill of Maher's
house for a particular month is RM75 and the rate of electricity consumption for that month is 294 kWh. If Maher wants to control
his variable expense to the maximum of only RM50 per month for electricity bill, what is the maximum rate of monthly electricity
consumption?
V ∝ R V = 98 R
V = kR 25
294 = k(75) V = 98 (50)
98 25
k =
25 V = 196 kWh
98
V = R
25
Cuba jawab Praktis SPM 1, K1: S11, K2: S4

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