Page 106 - Engineering Mathematics Workbook_Final

Differential Equations & Partial Differential Equations

1   4x + 4y + 1   134. The solution which transforms the
+
(b) tan − 1     = x c
2  2  non-homogenous differential
dy 2x + y + 6
equation = to
1 dx − x + − 3
y
+
(c) tan − 1 (4x + 4y + ) 1 = x c
2 homogenous form is
1 (a) x = X + 3, y Y + 1
=
c
(d) tan − 1 (4x + 4y + ) 1 =
2
=
(b) x = X + 3, y Y − 1
dy
132. The solution of = Sin (x + ) y is (c) x = X − 3, y Y +
=
dx 0
=
( +
) sec x y =
(a) tan x y − ( + ) x 2 + c (d) x = X − 3, y Y + 1
2
135. Which of the following differential
) tan x y =
(b) sec x y − ( + ) x 2 + c equation is linear
( +
2 dy
(a) + x y = 2 sin y
(
(c) tan x + y − ( ) y = + dx
) cos x +
x c
(
(d) tan x + y − ( ) y = + (b) dy − x y = 2 sin x
) cot x +
x c
dx
133. The solution of
y
y
dy =   + tan   is (c) (1 y ) dy + sin x =
 
+
 
0


x
x
dx       dx
 
 
 y  (d) dy + ( y y + ) x = x
2
(a) sin       = xc dx
 x 
dy
=
−
 y  136. The solution of + 2xy ex with
2
(b) tan       = xc dx
 x  y ( ) 0 = is
1
 y 
(c) Cosec       = xc (a) (1 x e+ ) x 2 (b) (1 x e+ ) − x 2
 x 
)
 y  (c) (1 x e− ) x 2 (d) (1 x e − x 2
−
(d) Cot       = xc
 x 

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