Page 413 - APPLIED PROCESS DESIGN FOR CHEMICAL AND PETROCHEMICAL PLANTS, Volume 1, 3rd Edition
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Ejectors and Mechanical  Vacuum Systems                            381

                               (                                   • Determine operating steam pressure, psig.
                                 u"
                             In�-   J                              • Determine/  establish  required  final  suction  pressure
                                 p"
                                  0                                  in vessel/system,  inches Hg abs.
              Solving:  t  =                            (6- 26)
                             In[    ,v   J                         • Establish  discharge  pressure  required  (usually  to
                         Rp,    v'  � �                              atmosphere), psig.
                                                                   • Note  that  the  performance  is  specific  Lo  the  ejector
                             ln(Q.01)                                used.
                                 760
                         (15 )  ln   (   500   )                 Example 6-14:  Evacuation of  Vessel Using Steam Jet for
                                 500  +  0.5                     Pumping Gases
                                                                   The performance  and  procedure use  the data of Pen-
                          ln  (0.0000131579)    -11. 23841862
                     t=                                          berthy for this illustration  (by permission):
                        (15)  In  (0. 999000999)   15  (-0.0009995003)

                     t  =  749.6 sec= 12.49 min                  Evacuating-Selection Procedure
           Evacuation With Steam Jets                              Refer to U  Evacuation Time chart.

           Rough Estimate of  System Pumpdown Using Steam  jets  [24  j   Step  1.  Determine  evacuation  time  in  minutes  per
                                                                 hundred cubic feel.
             The  remarks  presented  earlier  regarding  the  use  of
           steam jets for pumping down a system apply.  The method   Step 2. Go to  the left-hand column in table, final Suction
           of power [35]  presented by  Reference  [24]  is:     Pressure  (hs). Read across  to  find evacuation  time equal
                                                                 to or less than that determined in Step 1. Read to  the top
              t  =  [2.3  - 0.003  (I'',)] V  /wj        (6-27)   of table and note unit number.  See Table 6-15.

           where   t  =  lime required to evacuate a system from atmos-   Step  3.  Read  Steam  Consumption  of  unit  selected  off
                     pheric pressure Lo the steady state operating pres-   Capacity Factor Chart.  See Table 6-16.
                     sure,  min
                 P',  = design suction pressure of ejector,  torr   Evacuating-�LE:
                 V = free volume of the process system,  cu ft
                 "'.i  =  ejector capacity,  70°F dry air basis,  lb/hr   To  evacuate  3000  cubic  foot vessel  full  of air at  atmos-
                                                                 pheric pressure:
             This assumes dry air with no condensables and negligi-   Operating Steam Pressure,  PSJG  (hm)     100
           ble pressure drop through the system to the ejector.  Also,   Final Suction Pressure,  inches Hg abs  (hs)   5
           the jet  air  handling  capacity  is  assumed  approximately   Time to evacuate,  hrs                2.5
           twice the design capacity,  and air inleakage during evacu-   Discharge Pressure  (hd)        atmosphere
           ation is negligible.
             When  considering  time  to  evacuate  a  system  using  a   Step  1.  Determine  evacuation  time  in  minutes  per
           steam jet,  first recognize that securing reasonable accura-   hundred cubic feet.
           cy  is even  more  difficult than  for a  positive  displacement
           pump.  The efficiency of the ejector varies over its operat-
                                                                       2.5 hr X  60
           ing range; therefore as the differential  pressure across the   -------  =  5 min I  100 cu ft
           unit  varies,  so  will  the  volume  handled.  Consequently,   30  (hundred) cu fl
           evacuation  time  is  difficult to  establish  except in  broad   Step 2. Go to the final pressure on left of Evacuation Time
           ranges.  The  above  relations  can  be  adopted  to  establish   chart  (5 in.  Hg hs). Read across and find evacuation time
           the order of magnitude only.                          equal  lo or less than 5  minutes.  See Table 6-15.
             A recommended evacuation calculation  is given  in Ref:
           erence [ 19]. This is specific to Penberthy equipment,  but is   The U-2 will evacuate the tank in 5.33 minutes per hun-
           considered somewhat typical  of other manufacturers.   dred cubic feet and the U-3 will complete  the evacuation
                                                                 in 3.42  minutes per hundred cubic feet.
             • Establish suction load of air to be evacuated in cubic
               feet volume of  vessel/  system.                  Step  3.  Read  steam  consumption  of  selected  unit  off
              • Establish the  required  time to evacuate, in minutes.   Capacity  Factor Chart.  See Table  6-16.  The  unit to  select
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