Page 91 - Elementary Algebra Exercise Book I
P. 91
ELEMENTARY ALGEBRA EXERCISE BOOK I inequAlities
3.7 Solve the inequality lg(x − x − 6) < lg(2 − 3x).
2
Solution: The inequality holds if and only if
2
x − x − 6 > 0
2 − 3x> 0
2
x − x − 6 < 2 − 3x
⇒
x< −2 or x> 3
x< 2
3
−4 <x< 2
⇒−4 <x< −2, which is the solution of the original inequality.
3.8 a, b are real numbers and a + b =2, show a + b ≤ 2.
3
3
2
3
3
3
2
3
3
Proof: Suppose a + b> 2, then b> 2 − a ⇒ b > (2 − a) =8 − 12a +6a − a ⇒ a + b > 8 − 12a +6a =
3
3
2
3
2
3
3
b> 2 − a ⇒ b > (2 − a) =8 − 12a +6a − a ⇒ a + b > 8 − 12a +6a =
2
2
6a − 12a +6+2 = 6(a − 1) +2 > 2
b> 2 − a ⇒ b > (2 − a) =8 − 12a +6a − a ⇒ a + b > 8 − 12a +6a = 6a − 12a +6+2 = 6(a − 1) +2 > 2 , a contradiction to
2
3
3
3
3
3
2
2
2
2
2
6a − 12a +6+2 = 6(a − 1) +2 > 2 a + b =2. Hence, a + b ≤ 2.
3
3
Download free eBooks at bookboon.com Click on the ad to read more
Click on the ad to read more
Click on the ad to read more
Click on the ad to read more
Click on the ad to read more
Click on the ad to read more
Click on the ad to read more
Click on the ad to read more
Click on the ad to read more
Click on the ad to read more
Click on the ad to read more
Click on the ad to read more
Click on the ad to read more
Click on the ad to read more
Click on the ad to read more
Click on the ad to read more
Click on the ad to read more
Click on the ad to read more
Click on the ad to read more
Click on the ad to read more
Click on the ad to read more
Click on the ad to read more
Click on the ad to read more
Click on the ad to read more
Click on the ad to read more
Click on the ad to read more
Click on the ad to read more
Click on the ad to read more
Click on the ad to read more
91
91

